SQL查询中的一些疑问 [英] Some doubt in sql query

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本文介绍了SQL查询中的一些疑问的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在我的应用程序中,查询结果与网格视图绑定.

查询为]

In my application a query result is bind with a Grid View.

the query as ]

SELECT    tbl_DisclosureTypeDetails.disclodetDisclosureId,isnull( tbl_Disclosures.Disclosures,'''') AS Expr1,
convert(varchar(20), tbl_BorrowersMasterTemp.BMCurrDate,5),''closed'' as status,convert(varchar(20), tbl_DiscloTypeDetailsTemp.dtdTempDate,5)
FROM        ( tbl_DisclosureTypeDetails INNER JOIN
                      tbl_Disclosures ON tbl_DisclosureTypeDetails.disclodetDisclosureId = tbl_Disclosures.DiscId) 
INNER JOIN tbl_DiscloTypeDetailsTemp on tbl_DiscloTypeDetailsTemp.dtdTempDisclosureId=tbl_DisclosureTypeDetails.disclodetDisclosureId 
INNER JOIN tbl_BorrowersMasterTemp on tbl_BorrowersMasterTemp.BMId=tbl_DiscloTypeDetailsTemp.dtdTempId
WHERE     (tbl_DisclosureTypeDetails.disclodetMasterId = (SELECT     BMDisclosure
                            FROM          tbl_BorrowersMaster
                            WHERE      BMId = 221)) and tbl_DisclosureTypeDetails.disclodetDisclosureId not IN(SELECT 
   BMCDisclosures
FROM         tbl_BorrowersMasterChild
WHERE     (BMCBorrowerID = 221)) order by tbl_DisclosureTypeDetails.disclodetDisclosureId



该查询的结果是5列.

在此结果中,两列的值均与每一行相同.但是其他列重复使用5行或更多行.
我不能使用group by子句,因为每一行都不同.
因此,我该如何获取此表中的第五行或最新行.

放样

61 c1 10年10月5日08年10月5日
61 c1 08-05-10 08-05-10
61 c1 08-05-10 09-05-20
61 c1 09-06-10 10-06-10
61 c1 10-06-10 11-06-10
61 c1 11-06-10 12-06-10



The result of this query is 5 columns .

In this result Two columns values are change as in each row. But other columns are repeated with 5 or more rows.
I can''t use group by clause because of each row is different.
So How to I take fifth or latest row in this table.

Out put sample

61 c1 07-05-10 08-05-10
61 c1 08-05-10 08-05-10
61 c1 08-05-10 09-05-20
61 c1 09-06-10 10-06-10
61 c1 10-06-10 11-06-10
61 c1 11-06-10 12-06-10

推荐答案

所以您想获得最后一行?

如果对最后一列(desc)排序并使用TOP(1)
又怎么样? 那会帮助吗?
So you want to get the last row?

How about if you sort on your last column (desc) and use TOP(1)
Would that help?


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