Android的JSON对象在code一些问题没有能够得到从PHP JSON数组 [英] android json object some issue in code not able to get the json array from php

问题描述

我不能从PHP端得到​​如下数组对象

  {结果：sucess，数据：画的服务，水暖服务
电气服务，木工服务，铝作品，
家居清洁，家电，上光清洁，
院子里维护，水箱清洗
电子服务，室内装潢服务，干洗店，]，味精：Sucessfull}
 

这是从PHP端的json的反响

和使用im

 保护字符串doInBackground（字符串参数... args）{
                清单＆LT;＆的NameValuePair GT; userpramas =新的ArrayList＆LT;＆的NameValuePair GT;（）;
                //字符串A =（spinerplan.getSelectedItem（）的toString（））;
                userpramas.add（新BasicNameValuePair（PACKAGE_TYPE，glbstr_plan））;                JSONObject的JSON = jsonParser.makeHtt prequest（CommonClass.SERVIVECS_URL，POST，
                        userpramas）;
                //Log.e(\"testing，json的URL值=+ JSON）;
                尝试{                    字符串的反响= json.getString（数据）;                    JSONObject的servicejson =新的JSONObject（性反应）;
                    JSONArray jArray = servicejson.getJSONArray（数据）;                    的System.out.println（***** JARRAY *****+ jArray.length（））;                    的for（int i = 0; I＆LT; jArray.length（）;我++）{
                        JSONObject的json_data = jArray.getJSONObject（I）                        Log.e（测试，性反应+ json_data）;
                    }
                    Log.e（测试，性反应+的反响）;                }赶上（JSONException E）{
                    e.printStackTrace（）;
                }                返回的反响;
            }
 

解决方案

我觉得你的JSON响应是错误的。

您需要生成响应这样的..

  {结果：sucess，数据：[{serv_name：绘画服务}，
{serv_name：水暖服务}，{serv_name：电子服务}，
{serv_name：木工服务}，{serv_name：铝作品}，
{serv_name：家居清洁}，{serv_name：家电}，
{serv_name：上光清洁}，{serv_name：庭院维护}，
{serv_name：水油罐清洗}，{serv_name：电子服务}，
{serv_name：室内装潢服务}，{serv_name：干洗店}，
{serv_name：}]，味精：Sucessfull}
 

，那么你可以使用下面code解析响应..

 字符串的反响= json.getString（数据）;
JSONObject的servicejson =新的JSONObject（性反应）;
JSONArray jArray = servicejson.getJSONArray（数据）;
的System.out.println（***** JARRAY *****+ jArray.length（））;
的for（int i = 0; I＆LT; jArray.length（）;我++）{
   JSONObject的json_data = jArray.getJSONObject（I）
   串服务名= json_data.getString（serv_name）;
   Log.e（测试，性反应+服务名）;
}
Log.e（测试，性反应+的反响）;
 

I cant get the following array object from the php side

{"result":"sucess","data":["Painting service","Plumbing service", 
"Electrical service","Carpentry Services","Aluminium works",
"House Cleaning","Home Appliance","Glazing Cleaning",
"Yard Maintenance","Water Tank Cleaning",
"Electronics Services","Upholstery Services","DRY CLEANERS",""],"msg":" Sucessfull"}

this is my json responce from php side

and im using

   protected String doInBackground(String... args) {
                List<NameValuePair> userpramas = new ArrayList<NameValuePair>();
                //String a =(spinerplan.getSelectedItem().toString());
                userpramas.add(new BasicNameValuePair("package_type",glbstr_plan));

                JSONObject json = jsonParser.makeHttpRequest(CommonClass.SERVIVECS_URL, "POST",
                        userpramas);
                //Log.e("testing", "json url value=" + json);
                try {

                    String responce = json.getString("data");

                    JSONObject servicejson = new JSONObject(responce);
                    JSONArray jArray = servicejson.getJSONArray("data");

                    System.out.println("*****JARRAY*****" + jArray.length());

                    for(int i=0; i<jArray.length(); i++){
                        JSONObject json_data = jArray.getJSONObject(i);

                        Log.e("testing", "responce" + json_data);
                    }




                    Log.e("testing", "responce" + responce);

                } catch (JSONException e) {
                    e.printStackTrace();
                }

                return responce;
            }

解决方案

I think your JSON response is wrong..

You need to generate response like this..

{"result":"sucess","data":[{"serv_name":"Painting service"},
{"serv_name":"Plumbing service"},{"serv_name":"Electrical service"},
{"serv_name":"Carpentry Services"},{"serv_name":"Aluminium works"},
{"serv_name":"House Cleaning"},{"serv_name":"Home Appliance"},
{"serv_name":"Glazing Cleaning"},{"serv_name":"Yard Maintenance"},
{"serv_name":"Water Tank Cleaning"},{"serv_name":"Electronics Services"},
{"serv_name":"Upholstery Services"},{"serv_name":"DRY CLEANERS"},
{"serv_name":""}],"msg":" Sucessfull"}

then you can parse the response using below code..

String responce = json.getString("data");
JSONObject servicejson = new JSONObject(responce);
JSONArray jArray = servicejson.getJSONArray("data");
System.out.println("*****JARRAY*****" + jArray.length());
for(int i=0; i<jArray.length(); i++){
   JSONObject json_data = jArray.getJSONObject(i);
   String serviceName = json_data.getString("serv_name");
   Log.e("testing", "responce" + serviceName);
}
Log.e("testing", "responce" + responce);

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