如何在C ++中制作16 BYE数据类型? [英] How to Make a 16 bye data type in C++?

问题描述

如何使16字节数据时间可以执行以下操作:
添加
减法
乘法
DIVISION

how we can make a 16 byte data time with which we can perform following operations:
ADDITION
SUBTRACTION
MULTIPLICATION
DIVISION

推荐答案

ikramshah1写道:

ikramshah1 wrote:

16字节

真的是16个字节吗?您确定不是16位位(有很大的不同)吗?
如果它是16个字节，那么您将需要创建一个类并覆盖+，-，/和*运算符(在Google上搜索运算符重载).

如果它是16位，则可以使用缩写.

Is it really 16 bytes ? Are you sure it is not 16 bits (which makes a huge difference) ?
If it is 16 bytes, then you will need to create a class and override the +, -, / and * operators (search on google for operators overloading).

If it is 16 bits, then you can use a short.

假设数据类型为integer，则可以对执行所列操作的四个函数进行编码(例如，对两个)，毕竟，您可以手工计算非常大的数字(换句话说，您只需考虑进位").

Assuming your data type integer, you may code yourself the four functions performing the listed operations (for instance on two __int64), after all, by hand, you are able to compute operations on very big numbers (in other words you have just to consider ''carry'').

创建一个类并使用两个8字节整数或四个4字节整数封装16个字节.
重载+，-，*和/运算符，并在其中编写自己的逻辑以分别执行加法，减法，乘法和除法.

Create a class and encapsulate the 16 bytes either using two 8 byte integers or four 4 byte integers.
Overload the +, -, * and / operators and write your own logic in them to perform addition, subtraction, multiplication and division respectively.

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