如何从XML模式创建动态对象 [英] How to create dynamic object from XML Schema

问题描述

我想使用c#编码基于传递的xml模式创建新对象.
有可能吗?
我们如何创建对象?


谢谢
Saka

I want to create new object based on passed xml schema using c# coding.
Is it possible?
How can we create an object?


Thanks
Saka

推荐答案

成员2509982写道:

Member 2509982 wrote:

我们如何创建对象?

通过调用它的构造函数.如果您使用XML格式的数据，则可以读取传递给构造函数所需的值.

By calling it''s constructor. If you have the data in XML, you can read the values you need to pass to the constructor.

您必须a)知道架构的组织/内容，b)手动创建一个反映该架构的对象.此时，您可以将XML反序列化为对象的实例.

编辑==========

您还可以从xml创建数据集.

You have to a) know the organization/contents of the schema, and b) manually create an object that reflects that schema. At that point, you can deserialize the XML into an instance of object.

EDIT ==========

You could also create a dataset from xml.

HI，
我想基于XML Schema定义创建对象.
我们如何创建此动态对象?

谢谢
萨卡(Saka)

I want to create a object based on XML Schema definition.
How can we create this dynamic object?

Thanks
Saka

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