如何显示到Android的网页视图之前清除html页面？ [英] How to clear html page before showing into a webview in Android?
问题描述
我要显示到我的Android应用程序网页视图网页的URL。显示此页之前，我想从一些标记清除此页面的HTML code（如页眉，页脚，ECC ..），以显示只有少数的信息。我该怎么办呢？我试图解决JSoup工作问题，但我不明白如何创造和传递的新页的网页视图。任何人都可以帮我吗？
I have the URL of a webpage to be displayed into a webview in my Android app. Before showing this page i want to clear the html code of this page from some tag (such as the header, footer, ecc..) in order to show only few information. How can i do it? I tried to solve the issue working with JSoup but i can't understand how to create and pass the "new page" to the webview. Anybody can help me?
修改
我打扫HTML code到jsoup库没用。然后，总是通过这些意思，我让头部和身体的内容，最后我展示通过这些线的清除页面：
I cleaned the html code useless through jsoup libraries. Then, always by mean of these, i get head and body content and finally i showing the "cleared" web page through these lines:
headURL = doc.select("head").outerHtml();
bodyURL = doc.select("body").outerHtml();
webview.loadData( "<html>"+headURL+bodyURL+"</html>" , "text/html", "charset=UTF-8");
webview.setWebViewClient(new DisPlayWebPageActivityClient());
该视图显示了新的一页，但不加载在头部指定的CSS文件（尚未触及）。谁又能说我为什么？
The view shows the new page but do not load css files specified in the head(that has not been touched). Who can say me why?
推荐答案
您可以获取你想显示为一个字符串，解析并删除任何你不想再加载这个字符串作为你的WebView数据的网页。
You can fetch the WebPage you want to display as a string, parse and remove whatever you don't want and then load this string as data in your webview.
是这样的：
String webContent = fetchPage(url);
String cleanedWebContent = cleanUp(webContent);
webView.loadData(cleanedWebContent, "text/html", "UTF-8");
当然，你将需要实施 fetchPage 和清除，因为它们不是Android的方法
Of course, you will need to implement fetchPage and cleanUp as they are not Android methods
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