电话簿 .问题出在哪儿? [英] phonebook . where is the problem?

问题描述

我不知道为什么它不运行?它没有任何错误！

i dont know why it doesnt run? it doesnt have any error!

package importcontact;
 import java.util.Scanner;
   
 class PhoneEntry
 {
  String firstName;
  String lastName;
  String phone;
  PhoneEntry( String f, String l, String p ){
  firstName = f; lastName = l; phone = p;
      }
      }
   class PhoneBook{
   PhoneEntry[] phoneBook;
   PhoneBook() 
      {
phoneBook = new PhoneEntry[7 ] ;
phoneBook[0] = new PhoneEntry("James ", "Barclay ", "[phone]");
phoneBook[1] = new PhoneEntry("Grace" , "Dunbar", "[phone]");
phoneBook[2] = new PhoneEntry("Paul", "Kratides", "[phone]");
phoneBook[3] = new PhoneEntry("Violet" , "Smith", "[phone]");
phoneBook[4] = new PhoneEntry("John", "Smith", "[phone]");
phoneBook[5] = new PhoneEntry("Suleman", "Smith", "[phone]");
phoneBook[6] = new PhoneEntry("Violet", "Dunbar", "[phone]");
      }
PhoneEntry search( String lastName, String firstName){
for (int j=0; j<phoneBook.length; j++){
if ( phoneBook[ j ].lastName.equals( lastName) && phoneBook[ j ].firstName.equals( firstName))
return phoneBook[ j ];
 }
<pre lang="cs">return null;
}
public PhoneEntry[] search1( String lName){
int count=0;
for(int j=0; j<phoneBook.length; j++) {
if ( phoneBook[ j ].lastName.equals(lName)) count++;
}
if(count>0){
int k=0;
PhoneEntry pe[]=new PhoneEntry[count];
for(int j=0; j<phoneBook.length; j++) {
if ( phoneBook[ j ].lastName.equals(lName))
pe[k++]=phoneBook[j];
 }
 return pe;
 }
 return null;
 }
 class PhoneBookTester{
 public static void main (String[] args){
String firstName="";
String lastName="";
PhoneBook pb = new PhoneBook();
Scanner scan = new Scanner(System.in);
do {
System.out.println("Enter the last name or enter quit to terminate" );
lastName = scan.nextLine();
if(lastName.equals("quit")) break;
System.out.println("Enter the first name ");
firstName = scan.nextLine();
 // search for "Violet Smith"
PhoneEntry entry =pb.search( lastName, firstName );
PhoneEntry[] entry1 = pb.search1(lastName);
if(entry1.length==0){
System.out.println("No Match Found for :-both the entries -of -first & last names..");
}else{
 for(int i=0;i<entry1.length;i++){
 System.out.println( entry1[i].firstName + " "+entry1[i].phone);
 }
 }
if ( entry != null ) System.out.println( "The number is (of the entry matching both first & last name) " +entry.phone );
else
System.out.println("Name not found");
 }while(true);
 System.out.println("Good Bye ");
      }

      }

推荐答案

如果您不愿意匹配，请大括号，情况会大不相同:

If you bothered to match you''re braces, things would be rather different:

if ( phoneBook[ j ].lastName.equals(lName))
   count++;
}

与以下内容不同:

is not the same as:

if ( phoneBook[ j ].lastName.equals(lName))
{
   count++;
}

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