C语言winapi中的noob记事本克隆 [英] noob Notepad Clone in C winapi

问题描述

我正在使用《伪造者指南》(Forger's Tutorial)进行自我C WINAPI编程的教学，并决定制作一个记事本克隆.为了我的生命，我不知道如何辨别是否已选择文本"，因此可以动态启用和禁用菜单项.

I am teaching my self C WINAPI programming using the Forger''s Tutorial and decided to make a Notepad Clone. For the life of me I can not figure out how to tell if Text has been selected so I can Dynamically Enable and Disable Menu Items.

推荐答案

您使用的是什么控件?很难知道在C中可以使用什么功能，在C ++中，我确定文本框具有属性，并且可能是选择更改的事件.

您为什么选择学习C?它并没有太多用，当然也不是用来编写Windows程序.

What control are you using ? It''s hard to know what''s available to you in C, in C++ I am certain the textbox has properties and probably a selection changed event.

Why would you choose to learn C ? It''s not used for much of anything, and certainly not for writing windows programs.

我选择C是因为它是一个很好的开始.足够复杂以了解内部工作原理，但避免了对象的复杂性.我的议程中的下一个是Stromcodes教程，我敢肯定，有一种方法可以使用EM_GETSEL并比较WPARAM和LPARAM来确定它们是否相等，如果没有选择任何文本，则应该使用C_做到这一点(WPARAM和LPARAM应该如果未选择任何文本，都将返回光标位置). C ++正在我的眼前，但目前我对C#毫无兴趣.

I picked C because it is a good starting position. Complicated enough to get an understanding of the inner workings but avoids the complications of objects. Stromcodes tutorial is next on my agenda I am sure there is a way to do it in C something using the EM_GETSEL and comparing the WPARAM and LPARAM to see if they are equal, which they should be if no text is selected ( WPARAM and LPARAM should both return the cursor position if no text is selected ). C++ is on my horizon, but I have no interest in C# at this point in time.

您的推理是错误的. C ++比C有用得多，C只会教您如何编写BAD C ++代码.最好避免使用任何看起来像C的东西，并学习C ++. C#对于Windows编程更有用，但它与C或C ++根本无关，因此，如果您想学习一门更难的语言，则可以学习C ++，而C只会教您如何做事情很糟糕.

Your reasoning is faulty. C++ is far more useful than C, and C will only teach you how to write BAD C++ code. Far better to avoid anything that looks like C, and learn C++. C# is more useful for windows programming, but it''s not related to C or C++ at all, so if you want to learn a harder language, C++ is the one to learn, and C is only going to teach you how to do things badly.

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