为什么该程序没有结束创建的线程? [英] why does this program does not end the thread created??

问题描述

大家好，
下面的简单程序将使用CreateThread API创建两个线程，然后根据简单标志从该线程简单地返回，但是如果我在进程资源管理器中查看句柄，则创建的两个线程将不会结束

hi all,
the simple program below will create two threads using CreateThread API and then simply returns from the thread depending on the simple flag but two thread created will not be ended if i view the handles in process explorer

<br />
<br />
bool killthread1 = false,killthread2=false;<br />
void thread1()<br />
{<br />
        while(1)<br />
	{<br />
		if (killthread1)<br />
		{<br />
			printf("thread1 killed\n");<br />
			return;<br />
		}<br />
	}<br />
}<br />
<br />
void thread2()<br />
{<br />
	while(1)<br />
	{<br />
		if (killthread2)<br />
		{<br />
			printf("thread2 killed\n");<br />
			return;<br />
		}<br />
	}<br />
}<br />
<br />
int _tmain(int argc, _TCHAR* argv[])<br />
{<br />
	HANDLE th1 = CreateThread(NULL,0,(LPTHREAD_START_ROUTINE)(thread1),NULL,0,0);<br />
	HANDLE th2 = CreateThread(NULL,0,(LPTHREAD_START_ROUTINE)(thread2),NULL,0,0);<br />
	getch();<br />
	killthread1=killthread2=true;<br />
	getch();<br />
	return 0;<br />
}<br />

在调试模式下，visual studio显示2个线程在执行返回0之前已结束，但是进程资源管理器"显示它们仍处于活动状态，这是怎么回事?

In debug mode visual studio shows that 2 threads are ended before executing return 0, but "process explorer" shows they are alive, what is wrong in this??

推荐答案

写道:​​

bool killthread1 = false，killthread2 = false;

bool killthread1 = false,killthread2=false;

写道:​​

但如果我在进程浏览器中查看句柄，创建的两个线程将不会结束

but two thread created will not be ended if i view the handles in process explorer

这是因为用于检查线程终止条件的标志未声明为volatile.

因此，优化器必须完全删除支票！

请阅读以下内容: http://www.flounder.com/workerthreads.htm [

This is because the flags that you''re using to check for the thread termination condition is NOT declared as volatile.

Therefore, the optimiser must have completely removed the check!

Please read this: http://www.flounder.com/workerthreads.htm[^]

否，同时将两个BOOL都指定为volatile不变，VS显示两个都死了，但是进程浏览器"都显示为活着

NO assigning both BOOL as volatile also the scenario is not changing, VS shows both are dead, but the "process explorer" shows both as alive

Process Explorer显示内核线程对象还活着-您应该为CloseHandle() >和th2.

Process Explorer shows that the kernel thread objects are alive - you should call CloseHandle() for th1 and th2.

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