无法将int添加到int. [英] Cannot add int to a int.

问题描述

我正在编写一个程序来查找输入数字的平均值，但是我很难获取要显示的所有数字的总和.您能帮我用我编写的这段代码吗?

I am writing a program to find the average value of numbers entered but I am having difficulty getting the total value of all the numbers to show. Could you please help me with this code I have written?

谢谢

//program to find the average of values entered
#include <stdio.h>
int main()
{
  int sumOfValues = 0;
  int numberOfValueEntered = 0;
  int storage = 0;
  float averageOfValues = 0.0;

  printf("Enter a number or enter 0 to find the average of numbers entered\n");

  scanf("%i", &storage ); // reads the value and saves it in storage

  while (storage != 0) // when storage is not 0 carry out loop
  {
    ++numberOfValueEntered ; //adds one to numberOfValueEntered
    (storage += sumOfValues ); //adds the value of storage to sumOfValues 

    printf("%i,%i" ,numberOfValueEntered,sumOfValues); //test to see if numberOfValueEntered,sumOfValues is working correctly
    storage = 0; // return value of starage to 0
    printf("Please enter the next number or type 0 to exit\n");
    scanf("%i", &storage ); // reads the value and saves it in storage

  }// exits the loop when 0 is entered
  averageOfValues = (sumOfValues / numberOfValueEntered); //works out the average and stores it in averageOfValues
  //prints all the values averages etc
  printf("The results are as follows\n");
  printf("you have entered %d numbers, The total value of numbers entered is %i, and the average is %f",
    numberOfValueEntered,sumOfValues, averageOfValues); 

  return 0;
}

在尝试了答案之后，sumOfValues的值仍为0.有任何想法吗?

After trying the answers I am still getting a value of 0 for sumOfValues. Any ideas?

推荐答案

这正常工作

int sumOfValues = 0;
int numberOfValueEntered = 0;
int storage;
float averageOfValues;

printf("Enter a number or enter 0 to find the average of numbers entered: ");
scanf("%i", &storage ); // reads the value and saves it in storage
while (storage != 0) // when storage is not 0 carry out loop
{
    ++numberOfValueEntered ; //adds one to numberOfValueEntered
    sumOfValues += storage; //adds the value of storage to sumOfValues 
    printf("%i, %i\n" ,numberOfValueEntered,sumOfValues); //test to see if numberOfValueEntered,sumOfValues is working correctly
    printf("Please enter the next number or type 0 to exit: ");
    scanf("%i", &storage ); // reads the value and saves it in storage
}// exits the loop when 0 is entered
averageOfValues = (float)sumOfValues / (float)numberOfValueEntered; //works out the average and stores it in averageOfValues
//prints all the values averages etc
printf("The results are as follows\n");
printf("you have entered %d numbers\nThe total value of numbers entered is %i, and the average is %f\n",
numberOfValueEntered, sumOfValues, averageOfValues);

此行:

(storage += sumOfValues ); //adds the value of storage to sumOfValues //

错误.它的意思是: 

is wrong. it translates to:  

storage = storage + sumOfValues 

我怀疑您的意思是:

sumOfValues = sumOfValues + storage.  

，它的写法是这样的: 

which would be written like this:  

(sumOfValues += storage);

感谢您的答复，我已将其添加到我的代码中，但输入的总数仍为0，这反过来又使我平均获得了0.0，

thank you for the reply i have added it into my code and i am still getting a value of 0 for the total numbers entered which in turn is giving me an average of 0.0,

我不明白为什么它不会将值读入int.

i cant understand why it will not read the value into the int..

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