[不是问题] C编程中的逻辑问题 [英] [Not a question] logic problem in c programming

问题描述

我是C语言的初学者.我在逻辑上有问题.例如，汽车的可用性为1，但是当我插入要出租的汽车的数量大于1时，系统仍在运行，并且不输入if else语句.谢谢！

I''m beginner in C language.I have a problem with logic.For example, the availability of the car is 1,but when i insert the amount of the car i want to rent is more than 1, the system is still running and does not enter the if else statement.Thanks !

int car;
    int amountcarSAGA;
    int amountcarVIOS;

        printf(" Which car you prefer\n\t1 PROTON SAGA %d",availabilitySAGA);
        printf("\n\t2 TOYOTA VIOS\n\t");
        scanf("%d", &car );

        switch (car)
        {
          case 1 : if(availabilitySAGA<=0)
                   {
                       printf("No car available");
                       break;
                   }
                   else
                   {


                   printf("How many days you want to rent\n\t");
                   scanf("%d", &day);
                   printf("How many cars you want to rent\n\t");
                   scanf("%d",&amountcarSAGA);

                   if(availabilitySAGA>0)
                   {
                      calculation_carSAGA(day,amountcarSAGA);
                   }
                   else
                   {
                    printf("Amount of car exceed the availability");
                   }
                   availabilitySAGA=availabilitySAGA-amountcarSAGA;
                   break;
                   }

         case 2 : printf("How many days you want to rent\n\t");
                  scanf("%d", &day);
                  printf("How many cars you want to rent\n\t");
                   scanf("%d",&amountcarVIOS);
                   calculation_carVIOS(day,amountcarVIOS);
                   break;
         default: printf("\nEnter only one from the above");

        }

推荐答案

我的朋友，
这是一个显而易见的逻辑，即使您只有3辆车，用户也可以输入100辆车.原因说明如下...您可能必须阅读:P

1.您提供的第一个if条件是:

My Friend,
This is an obvious logic that user can enter 100 cars even if you only have 3 cars. The reason is explained below... You may have to read :P

1. The first if condition as per given by you is :

if (availabilitySAGA > 0) { // implies that SAGA is avialable even if one the condition is true
    // Rent the car to user
} else { // Now this condition is already checked by you previously before entring this if else condition am I right?
}

因此，这种情况是完全错误的.逻辑错误.

2.现在，逻辑应该是这样
->检查是否AvailabilitySAGA == 0''，因为您不想减价，所以可以吗?
->比较AvaialabilitySAGA> =输入的金额；这是正确的逻辑.
->根据条件的积极性做任何您想做的事情.

3.通常，在编写任何逻辑之前，通常应尝试进行纸笔模拟，即制作流程图和伪代码.由于您整夜过度调试，它将减少相当多的红眼:P

我试图以一种有趣的方式来表达它...希望它会有所帮助，尽管我已经读过您的评论，您可以自己解决问题.真的很棒. :)

致以问候
Tushar Srivastva

This condition thereby is completely wrong. The Logic is wrong.

2. Now, the logic should be this
-> Check if AvailabilitySAGA == 0 ''cause you are not going to go in minus can you?
-> Compare the AvaialabilitySAGA >= Entered amount; This is the correct logic.
-> Do whatever you want based on the positivity of the condition.

3. You generally should try to do a paper-pen simulation i.e. making flow charts and pseudo codes, before writing any logic. It will reduce considerable red eyes due to excessive debugging by you all night :P

I tried to put it in a fun way... Hope that it helped although I had read your comment already that you solved the problem yourself. It''s really good. :)

With Regards
Tushar Srivastva

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