如何从二进制文件中读取十六进制值并存储在十六进制数组中. [英] How read hex values from binary file and storing in a hex array.

问题描述

我需要读取binari文件的最后32个字节，并将它们用作十六进制数组(这是解密的密钥).
如果我使用诸如
的硬编码密钥

Hi, i need to read last 32 byte of a binari file and use them as array of hex (it''s a key for decryption).
if i use an hardcoded key like

unsigned char aesKey[32] = {
    0x53, 0x28, 0x40, 0x6e, 0x2f, 0x64, 0x63, 0x5d, 0x2d, 0x61, 0x77, 0x40, 0x76, 0x71, 0x77, 0x28,
    0x74, 0x61, 0x7d, 0x66, 0x61, 0x73, 0x3b, 0x5d, 0x66, 0x6d, 0x3c, 0x3f, 0x7b, 0x66, 0x72, 0x36
};

它可以工作，但是如果我尝试根据从文件读取的十六进制值创建aesKey数组，则会崩溃.

有什么想法吗?

从下面的非解决方案复制的其他信息
这就是我从文件中读取最后32个字节的方式:

it works, but if i try to create the aesKey array from hex values readed from file, it crash.

any ideas?

additional information copied from non-solution below
this is how i read the last 32 byte from my file:

char *chiavegiusta;
inFile.open(filename, ios::binary);
inFile.seekg(-32, ios::end);
inFile.read((char *)chiavegiusta, 32);
inFile.close();

我的问题是如何从这些值创建一个十六进制数组.

my problem is how to create an hex array from these values.

推荐答案

报价:

有什么想法吗?

是，可能您的程序无法正确读取文件中的数字.但是，您应该发布实际代码，以获得更好的帮助.

[更新]
您从未为数据分配内存.从
更改

Yes, probably your program doesn''t read correctly the numbers form the file. However, you should post the actual code, in order to get better help.

[update]
You never allocated memory for the data. change from

char *chiavegiusta;

到

to

unsigned char chiavegiusta[32];

[/update]

这就是我从文件中读取最后32个字节的方式:

this is how i read the last 32 byte from my file:

char *chiavegiusta;
    inFile.open(filename, ios::binary);
    inFile.seekg(-32, ios::end);
    inFile.read((char *)chiavegiusta, 32);
    inFile.close();

我的问题是如何从这些值创建一个十六进制数组.

my problem is how to create an hex array from these values.

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