C#中的百分比问题 [英] Percentage Problem In C#

问题描述

大家好！

我正在C#中创建标记百分比程序，但我仍然有百分比(0,0,0,0,0,0). 请告诉我其中的错误.

Hello Everyone!

I am Creating Marks Percentage Program In C#,but i still Got Percentage(0,0,0,0,0,0). Please Tell Me Error In It.

static void Main(string[] args)
{
    int[] number = new int[6];
    float[] percentage = new float[6];
    int x;
    Console.WriteLine("Enter Number.");
    for (x = 0; x < 6; x++)
    {
        Console.Write("Enter Subject {0} Marks.", x + 1);
        number[x] = Convert.ToInt32(Console.ReadLine());
    }
    Console.WriteLine("Percentaeg of Marks Is.");
    for (x = 0; x < 6; x++)
    {
        percentage[x] =(float)((number[x] / 100) * 100);
      //  Console.WriteLine(Math.Round(percentage[x]));
    }
    foreach (int per in percentage)
    {
        Console.WriteLine(per);
    }
    Console.ReadLine();

}

}

推荐答案

整数算术！
您的用户输入25个字.

Integer arithmetic!
Your user enters 25 say.

25 / 100 = 0

不是吗-这是整数运算，因此它不能使用分数.尝试更早地浮动:

No really - this is integer arithmetic, so it can''t work with fractions. Try changing to float earlier:

percentage[x] =(((float)number[x] / 100) * 100);

或先乘以:

Or multiply first:

percentage[x] =(float)((number[x] * 100) / 100);

或扔掉乘法和除法:

Or throw away the mutiplication and division:

percentage[x] =(float)number[x];

或者更好，在整个过程中使用浮点数:

Or better, use floats throughout:

float[] number = new float[6];
float[] percentage = new float[6];
int x;
Console.WriteLine("Enter Number.");
for (x = 0; x < 6; x++)
{
    Console.Write("Enter Subject {0} Marks.", x + 1);
    number[x] = Convert.ToFloat(Console.ReadLine());
}
Console.WriteLine("Percentaeg of Marks Is.");
for (x = 0; x < 6; x++)
{
    percentage[x] =(number[x] / 100) * 100;

，则乘法和除法是多余的！

But then, the multiplication and division are redundant!

.Net的数字处理让您着迷.将int 除以另一个int时，结果为int -它已经失去了所有小数位.现在，将其强制转换为float时，这些小数位将不再出现.

因此，您必须欺骗.Net进行所需的转换:

当您将int 除以float时，.Net会将int 转换为浮点数，结果是一个浮点数.好吧，double 可能是结果的类型，我不确定它的首选项.无论如何，double 是浮点数的常规使用"类型.

另外，将数字除以100并乘以100并不会改变它-您在这里感到困惑.汇总所有数字.

double[] percentage = new double[6];
percentage[x] = 100.0 * number[x] / sum;
100.0被解释为double，并且可以解决问题.

You were tricked by .Net''s number handling. When you divide an int by another int, the result is an int - it has already lost all its decimal places. When you now cast it to a float, those decimal places cannot appear again.

Hence you must trick .Net to do the conversions you need:

When you divide an int by a float, .Net converts the int to a floating point number, and the result is a floating point number. Well, double might be the type of the result, I am not fully sure about its preferences. Anyway, double is the "normally used" type of floating point numbers.

Also, dividing a number by 100 and multiplicating it by 100 doesn''t change it - you got confused here. Sum up all the numbers.

double[] percentage = new double[6];
percentage[x] = 100.0 * number[x] / sum;
100.0 is interpreted as a double, and that will do the trick.

除了OriginalGriff的回答，我建议阅读以下内容: float(C#参考) [

In addition of OriginalGriff''s answer, i''d suggest to read this: float (C# Reference)[^]. Follow the links provided on the bottom of relevant page.

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