如何在php中的2个选项卡中显示来自同一表的不同数据 [英] How to display different data from same table in 2 tabs in php
问题描述
大家好，我想在php中的2个不同选项卡中显示来自同一表的不同数据.当我选择负责人并在选项卡1中单击通知"时，它将被保存并显示在改善计划表中.但是，当我选择负责人并在选项卡2中单击通知"时，负责人将不会保存，也不会显示在Improvement_plan表中.请告知如何解决此问题.非常感谢.
< form action ="progress.php" method ="post" form name ="progress" id ="progress">
Hi everyone, I wanted to display different data from the same table in 2 different tabs in php. When i select the Responsible person and click Notify in tabs-1, it will be saved and displayed in the improvement_plan table. But when i select Responsible person and click Notify in tabs-2, Responsible person is not save and not display in the improvement_plan table. Please advise how to solve this matter. Thanks a lot.
<form action="progress.php" method="post" form name="progress" id="progress">
<输入type ="hidden" name ="Progressid" id ="Progressid" value =">
3.改进计划
<input type="hidden" name="Progressid" id="Progressid" value="">
3.Improvement Plan
团队负责人:<输入type ="text" readonly ="readonly" name ="Position" id ="Position" value =">
Team Leader:<input type="text" readonly="readonly" name="Position" id="Position" value="" >
mysql_close($con);
?>
<输入type ="hidden" name ="Progressid" id ="Progressid" value =">
3.改进计划
<input type="hidden" name="Progressid" id="Progressid" value="">
3.Improvement Plan
团队负责人:<输入type ="text" readonly ="readonly" name ="Position" id ="Position" value =">
Team Leader:<input type="text" readonly="readonly" name="Position" id="Position" value="" >
mysql_close($con);
?>
| <输入类型=提交" name ="submit" id =提交" value =保存" class ="btnSubmit"> |
</form>
| <input type="submit" name="submit" id="submit" value="Save" class="btnSubmit"> |
</form>
推荐答案
cn = mysql_connect("localhost"，"user"，")或die(mysql_error());
mysql_select_db("pq"，
cn=mysql_connect("localhost","user","") or die(mysql_error());
mysql_select_db("pq",
cn)或die(mysql_error());
cn) or die(mysql_error());
_SESSION ["Progressid"] =
_SESSION[''Progressid'']=
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