如何获得构造函数对象的显示属性 [英] How to get display properties of constructor object

问题描述

任务似乎很容易，但是我想我在这里遗漏了一些非常关键的要点. 我有一个看起来像这样的构造函数对象:

The task seems really easy but I think I am missing some very crucial point here.
I have a constructor object which looks like this:

function Person (name) {
  this.name = name;
  call = function (cellphone, callee){
   
  }
  return call;
  
}

然后我们初始化这个对象

Then we initialize this object

var dan = new Person("Dan");
var mark = new Person("Mark");
var phone = {owner: dan, number: "778-22-345"}
console.log(dan.call(phone, mark))

我想获得如下输出:

I would like to get the output which looks like this

"Dan called Mark from Dan`s phone [phone]"

如何访问这些属性?

我尝试过的事情:

我试图建立这样的调用方法
通话=功能(手机，被叫方){
返回名称+被叫" +被呼叫者名称+来自"+手机.所有者+电话" +手机号

}

How can I access those properties?

What I have tried:

I tried to build my call method like this
call = fucntion (cellphone, callee) {
return name + " called " + callee.name + " from " + cellphone.owner + "`s phone " + cellphone.number

}

推荐答案

首先，您的写作在JavaScript中有点危险！不要让JS决定将缺少的行尾(;)放在哪里-这可能会决定您错了...
还应在它属于它的任何时候使用它，并且不要忽略它！

您完全错误地定义了Person！创建它时，实际上是将call方法分配给新对象，因为结尾处是return call！
因此var dan = new Person(''Dan'');将dan设置为方法调用，而不是类Person !!!!!!

First of all your writing is a bit dangerous in JavaScript! Don''t let JS decide where to put thew missing line endings (;) - it will decide probably wrong for you...
Also use this whenever it belongs and do not omit it!

You defined Person in a totally wrong way! When you create it you actually assign the call method to the new object because of the return call at the end!!!

So var dan = new Person(''Dan''); sets dan to be the method call and NOT the class Person!!!

function Person (name) {
  this.name = name;
  
  this.call = function (cellphone, callee) {
    // your code here...
  };
};

面向对象的JavaScript简介-JavaScript | MDN [ ^ ]

Introduction to Object-Oriented JavaScript - JavaScript | MDN[^]

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