JAX-RS 2.0更改默认实现 [英] JAX-RS 2.0 change default implementation

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问题描述

我正在尝试将RESTEasy用作JAX-RS 2.0客户端实现.问题是我遇到了运行时异常:

I'm trying to use RESTEasy as JAX-RS 2.0 client implementation. The problem is that I got runtime exception:

06-28 13:29:06.410: E/AndroidRuntime(5745): Caused by: java.lang.RuntimeException: java.lang.ClassNotFoundException: org.glassfish.jersey.client.JerseyClientBuilder
06-28 13:29:06.410: E/AndroidRuntime(5745):     at javax.ws.rs.client.ClientBuilder.newBuilder(ClientBuilder.java:103)

因此,如果我理解正确的话,newBuilder()方法将搜索JerseyClientBuilder.如何告诉系统改用RESTEasy?

So the newBuilder() method is searching for JerseyClientBuilder if I understand it correct. How can I tell the system to use RESTEasy instead?

推荐答案

JAX-RS依赖于服务提供者约定. 在newBuilder方法的第一行中,您可以阅读:

Well, JAX-RS relies on the Service Provider convention. On the first lines of the newBuilder method you can read:

 Object delegate = FactoryFinder.find(JAXRS_DEFAULT_CLIENT_BUILDER_PROPERTY,
   JAXRS_DEFAULT_CLIENT_BUILDER); 

JAXRS_DEFAULT_CLIENT_BUILDER_PROPERTY"javax.ws.rs.client.ClientBuilder"

FactoryFinder看上去

  • 首先将类名放入META-INF/services/javax.ws.rs.client.ClientBuilder
  • 然后在属性javax.ws.rs.client.ClientBuilder中将其插入${java.home}/lib/jaxrs.properties
  • 最后进入系统属性javax.ws.rs.client.ClientBuilder.
  • first for the class name into META-INF/services/javax.ws.rs.client.ClientBuilder
  • then in the property javax.ws.rs.client.ClientBuilder into ${java.home}/lib/jaxrs.properties
  • finally into the System property javax.ws.rs.client.ClientBuilder.

因此,要使用RESTEasy,您应该创建一个文件

So, to use RESTEasy, you should create a file

META-INF/services/javax.ws.rs.client.ClientBuilder

带有文字:

org.jboss.resteasy.client.jaxrs.ResteasyClientBuilder

这是RESTEasy ClientBuilder的类名

which is the class name of the RESTEasy ClientBuilder

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