Java JDBC结果集错误,但是为什么呢? [英] Java JDBC result set error, but why?
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问题描述
Connection myConn = DriverManager.getConnection("jdbc:mysql://localhost:3306/dbname","user","pass");
Statement myStmt1 = myConn.createStatement();
System.out.println("connected");
for(int i=1; i<1375462;i++){
ResultSet myRs1 = myStmt1.executeQuery("SELECT Name FROM table WHERE id ="+i);
String Name = myRs1.getString("Name");
System.out.print(i);
System.out.println("Name:"+Name);
}
我正在使用JDBC Java从数据库查询名称,但这一次它出现了错误,我不知道为什么.我以前使用过Java JDBC.我可以连接到数据库,但是查询似乎无法正常工作? Id
列是10位整数.
I'm using JDBC Java to query the name from database but this time it got an error and I don't know why. I have used Java JDBC before. I can connect to database but the query seem like not working? Id
column is integer 10 digit.
"run: connected java.sql.SQLException: Before start of result set
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:959)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:898)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:887)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:862)
at com.mysql.jdbc.ResultSetImpl.checkRowPos(ResultSetImpl.java:790)
at com.mysql.jdbc.ResultSetImpl.getStringInternal(ResultSetImpl.java:5244)
at com.mysql.jdbc.ResultSetImpl.getString(ResultSetImpl.java:5167)
at com.mysql.jdbc.ResultSetImpl.getString(ResultSetImpl.java:5206)"
推荐答案
当您尝试在不移动光标的情况下访问某些内容时,会出现这种错误.尝试在获取String之前先放置myRs1.next();
.
This kind of error appears when you try to access something without moving cursor. Try to put myRs1.next();
before getting String.
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