如何使jmeter从每次迭代的响应中选择唯一值 [英] how to make jmeter to select unique values from response for each iteration

问题描述

我收到JMeter的以下回复:

I have the following response from JMeter:

{"tot_cnt":{"tc":"41651","rpp":"100","pdid":"1594"},"mg":[{"id":"683","rsd":"6-May-13 \/ 6-May-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/txq8xa56","inv":null,"rbp":"0","pdid":"106","di":"0","pl":"0","spl":null},{"id":"17670","rsd":"6-Jun-13 \/ 6-Jun-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/ckwu5qe8","inv":null,"rbp":"0","pdid":"106","di":"0","pl":"0","spl":null},{"id":"22","rsd":"22-Jul-13 \/ 22-Jul-13","col":"black","cc":"c_1884","pn":"old_THE ORTHODONTIC CLINC","loc":"15 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"15","cid":"1992","iq":"0","wid":"WI\/tldj53ky","inv":null,"rbp":"0","pdid":"1582","di":"0","pl":"0","spl":null},{"id":"686","rsd":"29-Jul-13 \/ 29-Jul-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/n4olde1g","inv":null,"rbp":"0","pdid":"107","di":"0","pl":"0","spl":null},{"id":"73","rsd":"5-Aug-13 \/ 5-Aug-13","col":"black","cc":"c_2357","pn":"old_KCA DEATAG","loc":"338 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"338","cid":"1914","iq":"0","wid":"WI\/zdqbx1zx","inv":null,"rbp":"0","pdid":"1578","di":"0","pl":"0","spl":null},{"id":"137","rsd":"5-Aug-13 \/ 5-Aug-13","col":"black","cc":"c_1219","pn":"old_TYPHOO - J01-TYPHOO- JULY 2013","loc":"56 - 24 \/ 81 \/ L3","isf":"1","isl":"0","tq":"2","pi":"0","st":"2","dsid":"56","cid":"2090","iq":"0","wid":"WI\/azdtc77c","inv":null,"rbp":"0","pdid":"1086","di":"0","pl":"0","spl":null},{"id":"70","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2394","pn":"old_SKF UK LTD","loc":"338 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"338","cid":"1914","iq":"0","wid":"WI\/45uzkvp3","inv":null,"rbp":"0","pdid":"1556","di":"0","pl":"0","spl":null},{"id":"1253","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2349","pn":"old_JUST TILES","loc":"PTD - 34 \/ 0M \/ MR","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"528","cid":"1955","iq":"0","wid":"WI\/ofunwm5s","inv":null,"rbp":"0","pdid":"1559","di":"0","pl":"0","spl":null},{"id":"1320","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2073","pn":"old_NEW COLLEGE SWINDON SUMMER CAMPAIGN","loc":"PTD - 34 \/ 0N \/ RS","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"528","cid":"1955","iq":"0","wid":"WI\/gpp1dejn","inv":null,"rbp":"0","pdid":null,"di":"0","pl":"0","spl":null},{"id":"27","rsd":"19-Aug-13 \/ 19-Aug-13","col":"black","cc":"c_2138","pn":"old_WIRED STUDIO PEAK MEGA REAR","loc":"15 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"15","cid":"1992","iq":"0","wid":"WI\/b5m0iyuc","inv":null,"rbp":"0","pdid":"1597","di":"0","pl":"0","spl":null},{"id":"561","rsd":"19-Aug-13 \/ 19-Aug-13","col":"black","cc":"c_3737","pn":"old_LONDON ROAD BRIDGE SCHEME DERBY CITY COUNCIL","loc":"PTD - 83 \/ 4I \/ WB","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/1s1xaqxw","inv":null,"rbp":"0","pdid":"2574","di":"0","pl":"0","spl":null}

我使用了(?=(?:(?!isf).)*?isf":"1)(?=(?:(?!isl).)*?isl":"0)(?=(?:(?!st).)*?st":"2)"id":"(\d+)正则表达式来选择所需的ID.

I used (?=(?:(?!isf).)*?isf":"1)(?=(?:(?!isl).)*?isl":"0)(?=(?:(?!st).)*?st":"2)"id":"(\d+) regular expression to select the required id.

当我使用5个用户运行测试时，在几次测试中，对于不同的迭代会选择相同的ID，从而导致错误.

When I run the test using 5 users, during few tests same id is selected for different iterations causing error.

我需要让jmeter从每次迭代的响应中提取一些唯一的值. 我怎样才能做到这一点?提前致谢.

I need to make jmeter extract some unique values from response for each iteration. How can I do that? Thanks in advance.

推荐答案

临时解决方案:

在正则表达式提取器"中，保留设置匹配号".为"0"

In your "Regular Expression Extractor", keep the setting "Match No." as "0"

即使ID并非唯一，但ID也会随机选择不同的值，而不是再次选择相同的值&再次.

Even tough the ID's will not be unique but it will randomly select different values rather than selecting same value again & again.

完整的解决方案:

使用Bean Shell Sampler将所有有效的"ID"写入第一线程组" 中的CSV文件中 &然后
在第二线程组" 中，使用创建的CSV(每个请求的唯一值)运行测试.

write all the valid "ID" to CSV file in "1st Thread group" using Bean Shell Sampler & then
In the "2nd Thread Group" run the test using created CSV with unique values for each request.

在分析结果时，您可以忽略第一个线程组.

While analyzing the results you can ignore 1st thread group.

希望这会有所帮助.

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