pandas :通过多列查找另一个DataFrame中不存在的行 [英] Pandas: Find rows which don't exist in another DataFrame by multiple columns

问题描述

与此相同python pandas:如何在一个数据框中找到行而在另一个数据框中找不到行? 但有多列

这是设置:

import pandas as pd

df = pd.DataFrame(dict(
    col1=[0,1,1,2],
    col2=['a','b','c','b'],
    extra_col=['this','is','just','something']
))

other = pd.DataFrame(dict(
    col1=[1,2],
    col2=['b','c']
))

现在，我想从df中选择其他行中不存在的行.我想通过col1和col2

Now, I want to select the rows from df which don't exist in other. I want to do the selection by col1 and col2

在SQL中，我会这样做:

In SQL I would do:

select * from df 
where not exists (
    select * from other o 
    where df.col1 = o.col1 and 
    df.col2 = o.col2
)

在Pandas中，我可以做这样的事情，但是感觉非常丑陋.如果df具有id列，则可以避免部分丑陋，但它并不总是可用.

And in Pandas I can do something like this but it feels very ugly. Part of the ugliness could be avoided if df had id-column but it's not always available.

key_col = ['col1','col2']
df_with_idx = df.reset_index()
common = pd.merge(df_with_idx,other,on=key_col)['index']
mask = df_with_idx['index'].isin(common)

desired_result =  df_with_idx[~mask].drop('index',axis=1)

所以也许有一些更优雅的方式?

推荐答案

由于0.17.0，有一个新的

Since 0.17.0 there is a new indicator param you can pass to merge which will tell you whether the rows are only present in left, right or both:

In [5]:
merged = df.merge(other, how='left', indicator=True)
merged

Out[5]:
   col1 col2  extra_col     _merge
0     0    a       this  left_only
1     1    b         is       both
2     1    c       just  left_only
3     2    b  something  left_only

In [6]:    
merged[merged['_merge']=='left_only']

Out[6]:
   col1 col2  extra_col     _merge
0     0    a       this  left_only
2     1    c       just  left_only
3     2    b  something  left_only

因此，您现在可以通过仅选择'left_only'行

So you can now filter the merged df by selecting only 'left_only' rows

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