使用Oracle数据库的JOIN语法进行更新 [英] UPDATE with JOIN syntax for Oracle Database
问题描述
首先,我执行以下SQL语句.
First, I execute the following SQL statements.
drop table names;
drop table ages;
create table names (id number, name varchar2(20));
insert into names values (1, 'Harry');
insert into names values (2, 'Sally');
insert into names values (3, 'Barry');
create table ages (id number, age number);
insert into ages values (1, 25);
insert into ages values (2, 30);
insert into ages values (3, 35);
select * from names;
select * from ages;
因此,将创建以下表.
ID NAME
---------- ----------
1 Harry
2 Sally
3 Barry
ID AGE
---------- ----------
1 25
2 30
3 35
现在,我想将Sally的年龄增加1,即将其设置为31.下面的查询可以正常工作.
Now, I want to update increment the age of Sally by 1, i.e. set it to 31. The following query works fine.
update ages set age = age + 1 where id = (select id from names where name = 'Sally');
select * from ages;
表格现在看起来像这样.
The table now looks like this.
ID AGE
---------- ----------
1 25
2 31
3 35
我想知道是否有一种方法可以通过联接来完成.例如,我尝试了以下查询,但失败了.
I want to know if there is a way it can be done by joins. For example, I tried the following queries but they fail.
SQL> update ages set age = age + 1 from ages, names where ages.id = names.id and names.name = 'Sally';
update ages set age = age + 1 from ages, names where ages.id = names.id and names.name = 'Sally'
*
ERROR at line 1:
ORA-00933: SQL command not properly ended
SQL> update ages set age = age + 1 from names join ages on ages.id = names.id where names.name = 'Sally';
update ages set age = age + 1 from names join ages on ages.id = names.id where names.name = 'Sally'
*
ERROR at line 1:
ORA-00933: SQL command not properly ended
推荐答案
UPDATE语句的语法为:
The syntax of the UPDATE statement is:
http://docs.oracle.com/cd /B19306_01/server.102/b14200/statements_10007.htm
其中dml_table_expression_clause
是:
请注意上述语法的( subquery )
部分.
Please pay attention on ( subquery )
part of the above syntax.
subquery
是一项允许执行联接更新的功能.
The subquery
is a feature that allows to perform an update of joins.
最简单的形式可以是:
UPDATE (
subquery-with-a-join
)
SET cola=colb
在更新联接之前,您必须了解此处列出的限制:
Before update a join, you must know restrictions listed here:
https://docs.oracle.com/cd /B28359_01/server.111/b28286/statements_8004.htm
该视图不得包含以下任何构造:
The view must not contain any of the following constructs:
- 集合运算符
- DISTINCT运算符
- 聚合或分析函数
- GROUP BY,ORDER BY,MODEL,CONNECT BY或START WITH子句
- SELECT列表中的集合表达式
- SELECT列表中的子查询
- 指定为WITH READ的子查询
- 加入(除某些例外),如《 Oracle数据库管理员指南》中所述
- A set operator
- A DISTINCT operator
- An aggregate or analytic function
- A GROUP BY, ORDER BY, MODEL, CONNECT BY, or START WITH clause
- A collection expression in a SELECT list
- A subquery in a SELECT list
- A subquery designated WITH READ ONLY
- Joins, with some exceptions, as documented in Oracle Database Administrator's Guide
以及与可更新视图相关的通用规则-此处(第Updating a Join View
节):
http://docs.oracle.com /cd/B19306_01/server.102/b14231/views.htm#sthref3055
and also common rules related to updatable views - here (section: Updating a Join View
):
http://docs.oracle.com/cd/B19306_01/server.102/b14231/views.htm#sthref3055
联接视图的所有可更新列都必须映射到一个 保留键的表.请参阅密钥保存表",以获取有关的内容的讨论. 保留键的表.如果视图是使用WITH CHECK定义的 OPTION子句,然后所有联接列和所有重复列 表不可更新.
All updatable columns of a join view must map to columns of a key-preserved table. See "Key-Preserved Tables" for a discussion of key-preserved tables. If the view is defined with the WITH CHECK OPTION clause, then all join columns and all columns of repeated tables are not updatable.
我们首先可以创建一个带有联接的子查询:
We can first create a subquery with a join:
SELECT age
FROM ages a
JOIN names m ON a.id = m.id
WHERE m.name = 'Sally'
此查询仅返回以下结果:
This query simply returns the following result:
AGE
----------
30
现在我们可以尝试更新查询:
and now we can try to update our query:
UPDATE (
SELECT age
FROM ages a
JOIN names m ON a.id = m.id
WHERE m.name = 'Sally'
)
SET age = age + 1;
但是我们得到一个错误:
but we get an error:
SQL错误:ORA-01779:无法修改映射到非键保留表的列
SQL Error: ORA-01779:cannot modify a column which maps to a non key-preserved table
此错误表示不满足上述限制之一(保留键的表).
This error means, that one of the above restriction is not meet (key-preserved table).
但是,如果我们向表中添加主键:
However if we add primary keys to our tables:
alter table names add primary key( id );
alter table ages add primary key( id );
然后,此更新可以正常进行,并且最终结果是:
then now the update works without any error and a final outcome is:
select * from ages;
ID AGE
---------- ----------
1 25
2 31
3 35
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