多个内部联接在php中不起作用 [英] multiple inner join not working in php
问题描述
所以我得到了在mysql phpmyadmin中完全可以使用的查询，但是当我在php文件中使用它时却无法使用.
so i got this query that is fully working in mysql phpmyadmin but its not working when i use it in a php file.
SELECT *
FROM services_package
JOIN service_in_package
ON services_package.id = service_in_package.package_id
JOIN itv
ON service_in_package.service_id = itv.id
JOIN tv_genre
ON itv.tv_genre_id = tv_genre.id
WHERE services_package.id = 25
知道为什么吗?
我已经尝试过多次了，问题出在这里:
i already tried it multiple times and the problem is somewhere here:
INNER JOIN tv_genre ON itv.tv_genre_id = tv_genre.id
这是php代码:
$sql = "
SELECT *
FROM services_package
JOIN service_in_package
ON services_package.id = service_in_package.package_id
JOIN itv
ON service_in_package.service_id = itv.id
JOIN tv_genre
ON itv.tv_genre_id = tv_genre.id
WHERE services_package.id = 25
";
$rows = array();
$result = $conn->query($sql);
if($result->num_rows > 0)
{
while($r = mysqli_fetch_assoc($result)) {
$rows[] = $r;
}
echo json_encode($rows);
} 好的，所以我没有任何错误.即使打开了错误.循环循环了8次(这是正确的原因，因为它应该返回8行)，但是没有输出.
} okay, so i get no errors. even with errors turned on. the loop is looping 8 times (which is correct cause it should return 8 rows) but it has no output.
它实际上在以下时间起作用:
it actually is working when :
INNER JOIN tv_genre ON itv.tv_genre_id = tv_genre.id
已删除.我很困惑.
更新: 我检查了phpmyadmin中的行，并发现多行具有相同的名称"ID"，并认为这可能会在向JSON的转换中产生冲突，因此我进行了新查询:
UPDATE: i checked the rows in phpmyadmin and noticed that multiple rows had the same name 'ID' and thought it could create a conflict in the conversion to JSON so i made a new query:
SELECT itv.id AS channel_id,
tv_genre.id AS genre_id,
services_package.id AS service_package_id,
itv.name AS channel_name,
itv.descr AS channel_description,
services_package.type AS channel_type,
itv.number, itv.censored,
itv.cmd AS channel_source,
tv_genre.title AS genre_name,
itv.logo
FROM services_package
JOIN service_in_package ON services_package.id = service_in_package.package_id
JOIN itv ON service_in_package.service_id = itv.id
JOIN tv_genre ON itv.tv_genre_id = tv_genre.id
WHERE services_package.id =25
正在phpmyadmin中工作，而不在php文件中工作:/
which is working in phpmyadmin and not working in a php file :/
var_dump结果(出于明显原因更改了channel_source):
var_dump result(changed the channel_source for obvious reasons):
array(11) { ["channel_id"]=> string(3) "846" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(8) "HAC 2 HD" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "5" ["censored"]=> string(1) "0" ["channel_source"]=> string(45) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "845" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(8) "HAC 1 HD" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "4" ["censored"]=> string(1) "0" ["channel_source"]=> string(44) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "831" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(9) "HAC 3 HD " ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "6" ["censored"]=> string(1) "0" ["channel_source"]=> string(45) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "829" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(8) "HAC SD 3" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "3" ["censored"]=> string(1) "0" ["channel_source"]=> string(39) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "828" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(8) "HAC SD 2" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "2" ["censored"]=> string(1) "0" ["channel_source"]=> string(39) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "814" ["genre_id"]=> string(2) "10" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(13) "Go To Luxe.TV" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(2) "23" ["censored"]=> string(1) "0" ["channel_source"]=> string(41) "http://test.com" ["genre_name"]=> string(8) "Englisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "808" ["genre_id"]=> string(1) "8" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(16) "Nature & Animaux" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(2) "10" ["censored"]=> string(1) "0" ["channel_source"]=> string(36) "http://test.com" ["genre_name"]=> string(11) "Französisch" ["logo"]=> string(0) "" } array(11) { ["channel_id"]=> string(3) "807" ["genre_id"]=> string(1) "8" ["service_package_id"]=> string(2) "25" ["channel_name"]=> string(8) "HAC SD 1" ["channel_description"]=> string(0) "" ["channel_type"]=> string(2) "tv" ["number"]=> string(1) "1" ["censored"]=> string(1) "0" ["channel_source"]=> string(39) "http://test.com" ["genre_name"]=> string(11) "Französisch" ["logo"]=> string(0) "" }
我现在唯一能想到的就是在将结果转换为JSON时出了点问题
the only thing i can think of right now is that something goes wrong while converting the result to JSON
推荐答案
已解决！问题是我的mysql结果包含一些无法转换为JSON的字符，请使用此函数对其进行修复:
function utf8ize($mixed) {
if (is_array($mixed)) {
foreach ($mixed as $key => $value) {
$mixed[$key] = utf8ize($value);
}
} else if (is_string ($mixed)) {
return utf8_encode($mixed);
}
return $mixed;
}
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