将字符串转换为其ascii值的整数 [英] Convert a string into an integer of its ascii values

问题描述

我正在尝试编写一个接受字符串txt并返回该字符串的字符的ascii数字的int的函数.它还需要第二个参数n，它是一个整数，它指定每个字符应转换为的位数. n的默认值为3.n始终> 3，并且字符串输入始终为非空.

I am trying to write a function that takes a string txt and returns an int of that string's character's ascii numbers. It also takes a second argument, n, that is an int that specified the number of digits that each character should translate to. The default value of n is 3. n is always > 3 and the string input is always non-empty.

示例输出:

string_to_number('fff')
102102102

string_to_number('ABBA', n = 4)
65006600660065

我当前的策略是通过将txt转换为列表来将其拆分为字符.然后，我将字符转换为它们的ord值，并将其附加到新列表中.然后，我尝试将这个新列表中的元素组合成一个数字(例如，我将从['102', '102', '102']转到['102102102'].然后，我尝试将该列表的第一个元素(也称为唯一元素)转换为整数.我当前的代码如下:

My current strategy is to split txt into its characters by converting it into a list. Then, I convert the characters into their ord values and append this to a new list. I then try to combine the elements in this new list into a number (e.g. I would go from ['102', '102', '102'] to ['102102102']. Then I try to convert the first element of this list (aka the only element), into an integer. My current code looks like this:

def string_to_number(txt, n=3):
    characters = list(txt)
    ord_values = []


for character in characters:
    ord_values.append(ord(character))

    joined_ord_values = ''.join(ord_values)
    final_number = int(joined_ord_values[0])

    return final_number

问题是我得到了Type Error.我可以编写成功返回单字符字符串整数的代码，但是对于包含多个字符的字符，由于这种类型错误，我不能这样做.有什么办法解决这个问题.谢谢，如果很长的话，我们深表歉意.

The issue is that I get a Type Error. I can write code that successfully returns the integer of a single-character string, however when it comes to ones that contain more than one character, I can't because of this type error. Is there any way of fixing this. Thank you, and apologies if this is quite long.

推荐答案

尝试一下:

def string_to_number(text, n=3):
    return int(''.join('{:0>{}}'.format(ord(c), n) for c in text))

print(string_to_number('fff'))
print(string_to_number('ABBA', n=4))

输出:

102102102
65006600660065

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编辑:不带列表理解，如OP在评论中要求的那样

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without list comprehension, as OP asked in the comment

def string_to_number(text, n=3):
    l = []
    for c in text:
        l.append('{:0>{}}'.format(ord(c), n))
    return int(''.join(l))

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有用的链接:

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Useful link(s):

• Python中的字符串格式:包含您需要了解的几乎所有内容python中的字符串格式

• string formatting in python: contains pretty much everything you need to know about string formatting in python

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