独家完全加入 [英] Exclusive Full Join in r
问题描述
试图在r代码中实现排他的完全联接.
Trying to implement exclusive full join in r code.
实现了以下代码,该代码可以正常运行,但由于过滤器充满了很多条件,因此是正确的方法.由于这是示例代码,因此没有添加太多列,但是在实时场景中,我们有很多列,因此将这些列加起来进行过滤将使事情变得困难.
Implemented the below code which works correctly but is the correct approach since the filter is filled lots of conditions. Since this is the sample code didn't add much columns but in real time scenario we have many columns so adding up the columns to filter would make things difficult.
那么还有其他更好的方法可用吗?
library(tidyverse)
persons = data.frame(
name = c("Ponting", "Clarke", "Dave", "Bevan"),
age = c(24, 32, 26, 29),
col1 = c(1,2,3,4),
col2 = c("a", "z", "h", "p")
)
person_sports = data.frame(
name = c("Ponting", "Dave", "Roshan"),
sports = c("soccer", "tennis", "boxing"),
rank = c(8, 4, 1),
col3 = c("usa", "australia", "england"),
col4 = c("a", "f1", "z2")
)
persons %>% full_join(person_sports, by = c("name")) %>%
filter((is.na(age) & is.na(col1) & is.na(col2)) | (is.na(sports) & is.na(rank) & is.na(col3) & is.na(col4)))
输出:
推荐答案
尝试使用complete.cases
.这将返回一个TRUE/FALSE向量,其中FALSE表示在至少一列的给定行中找到了NA.
Try using complete.cases
. This will return a vector of TRUE/FALSE where FALSE indicates an NA is found on a given row in at least one column.
persons %>% full_join(person_sports, by = c("name")) %>% .[!complete.cases(.), ]
# name age col1 col2 sports rank col3 col4
# 2 Clarke 32 2 z <NA> NA <NA> <NA>
# 4 Bevan 29 4 p <NA> NA <NA> <NA>
# 5 Roshan NA NA <NA> boxing 1 england z2
作为替代方法,其工作原理与上述类似,请使用dplyr
软件包中的filter_all
和any_vars
.
As an alternative, which works similarly to the above, use filter_all
and any_vars
from the dplyr
package.
persons %>% full_join(person_sports, by = c("name")) %>% filter_all(any_vars(is.na(.)))
# name age col1 col2 sports rank col3 col4
# 1 Clarke 32 2 z <NA> NA <NA> <NA>
# 2 Bevan 29 4 p <NA> NA <NA> <NA>
# 3 Roshan NA NA <NA> boxing 1 england z2
最后,由于您提到了实际的数据集要大得多,因此您可能想与data.table
解决方案进行比较,看看哪种数据在您的实际数据中最有效.
Finally, since you mentioned your actual dataset is much bigger, you might want to compare to a data.table
solution and see what works best in your real world data.
library(data.table)
setDT(persons)
setDT(person_sports)
merge(persons, person_sports, by = "name", all = TRUE) %>% .[!complete.cases(.)]
# name age col1 col2 sports rank col3 col4
# 1: Bevan 29 4 p NA NA NA NA
# 2: Clarke 32 2 z NA NA NA NA
# 3: Roshan NA NA NA boxing 1 england z2
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