如何选择某些"id"的总和并按组划分结果 [英] How to select sums of certain 'id' and devide the result by groups

问题描述

在此查询中，我尝试选择用户已付款的金额:

In this query I try to select the sums of payments the users had made:

SELECT *
from (select IFnull(t.diapason,'total') as diapason,
t.total_amount as total_amount 

FROM 
(SELECT p.user_id, p.amount as total_amount, CASE
when amount<=100 then '0-100'
when amount>100 then '100...' END AS diapason
FROM (SELECT distinct payments.user_id, SUM(amount) AS amount 
FROM payments inner JOIN (SELECT DISTINCT user_id FROM payments where 
     payment_time between '2000-01-01' and '2001-01-01') a ON 
payments.user_id = a.user_id 
GROUP BY payments.user_id) p) t  
GROUP BY diapason WITH ROLLUP) as t1  
ORDER BY total_amount desc;

但是我得到的结果是错误的.我应该更改什么才能找出2000年1月1日至2001年1月1日之间的工资总额.由于用户曾经付款，结果必须按组划分.

But result I've got is wrong. What should I change to find out sum of paymens for period 2000-01-01 - 2001-01-01. Result must be devided by group due to payments user ever did.

这些是表格的活动和付款.

These are tables activity and payments.

activity
user_id   login_time
1         2000-01-01
2         2000-03-01
....

payments
user_id     payment_time    amount
1          2000-05-04        10
1          2000-03-01        20
2          2000-04-05        5
...

通常，组由每个用户曾经支付的总金额组成.例如，如果他支付了50美元-他在"0-100"组中.如果他支付了500，那么他就属于"100 ..."组，但是现在我需要知道每个组中用户的付款总额.

Generally, groups formed by total amount each user ever payed. For example if he payed 50 $ - he is in group "0-100". If he payed 500 - he is in the group "100..." But now I need to know sum of payments users made in each group.

谢谢您的帮助！

推荐答案

如果我正确理解，则不需要所有这些子查询. 简单的sum和group by应该做到这一点:

If I understood correctly, no need for all those sub-queries. Simple sum and group by should do it:

SELECT t1.user_id, sum(t2.amount) as total, IF(sum(t2.amount)<=100, '0-100',  '100...') as grp 
FROM t1
INNER JOIN t2 on t1.user_id = t2.user_id
WHERE t2.payment_time between '2000-01-01' and '2001-01-01'
GROUP BY t1.user_id

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