如何使用JPA/EclipseLink进行级联持久化 [英] How to cascade persist using JPA/EclipseLink

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本文介绍了如何使用JPA/EclipseLink进行级联持久化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在对父实体执行级联持久化操作时遇到问题.当子实体持久存在时,对父实体的引用(生成的ID)为null.我如何才能使它正确持续?

I am having problems performing a cascade persist operation on a parent entity. When the child entity is persisted, the reference (generated id) to the parent entity is null. How would I get this to persist correctly?

实体:

@Entity
public class Contact {

        @Id @GeneratedValue(strategy=GenerationType.TABLE, generator="contact_gen")
        @TableGenerator(name="contact_gen",
            table="id_gen", pkColumnName="gen_name", 
            valueColumnName="gen_val", pkColumnValue="cont_gen")
        @Column(name="contact_id")
        private Long id;

        @Column(name="name")
        private String name;

        @OneToMany(mappedBy="contact", cascade=CascadeType.PERSIST)
        private List<Address> addresses = new ArrayList<Address>();

        public void addAddress(Address address) {
             addresses.add(address);
        }

        ...
}

@Entity
public class Address {

        @Id @GeneratedValue(strategy=GenerationType.TABLE, generator="address_gen")
        @TableGenerator(name="address_gen",
            table="id_gen", pkColumnName="gen_name", 
            valueColumnName="gen_val", pkColumnValue="addr_gen")
        @Column(name="address_id")
        private Long id;

        @Column(name="full_address")
        private String fullAddress;

        @ManyToOne
        @JoinColumn(name="contact_id")
        private Contact contact;

        ...
}

服务:

@Stateless
public class ContactService {

    @PersistenceContext
    private EntityManager em;

    public void createContact() {   
        Contact contact = new Contact();
        contact.setName("Michael Scott");
        contact.addAddress(new Address("1725 Slough Avenue");
        em.persist(contact);        
    }

}

MySQL Tables&插入:

MySQL Tables & Inserts:

CREATE TABLE `contact` (
  `contact_id` int(11) NOT NULL,
  `name` varchar(45) NOT NULL
  PRIMARY KEY (`contact_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

CREATE TABLE `address` (
  `address_id` int(11) NOT NULL,
  `full_address` varchar(100) NOT NULL,
  `contact_id` int(11) NOT NULL,
  PRIMARY KEY (`address_id`),
  KEY `FK_ADDRESS_contact_id` (`contact_id`),
  CONSTRAINT `FK_ADDRESS_contact_id` FOREIGN KEY (`contact_id`) REFERENCES `contact` (`contact_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

CREATE TABLE id_gen (
    gen_name VARCHAR(80),
    gen_val INT,
    PRIMARY KEY (gen_name)
);
INSERT INTO id_gen (gen_name, gen_val) VALUES ('cont_gen', 0);
INSERT INTO id_gen (gen_name, gen_val) VALUES ('addr_gen', 0);

推荐答案

不幸的是,您没有显示addAddress的内容.由于您的关联是双向的,因此您是否要在这种方法中设置链接双方"?像这样:

Sadly, you're not showing the content of addAddress. Since your association is bidirectional, are you setting "both sides of the link" in this method? Something like this:

@Entity
public class Contact {

    ...

    @OneToMany(mappedBy="contact", cascade=CascadeType.PERSIST)
    private List<Address> addresses = new ArrayList<Address>();

    public void addToAddresses(Address address) {
        address.setContact(this);
        this.addresses.add(address);
    }
}

这篇关于如何使用JPA/EclipseLink进行级联持久化的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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