JPA JPQL:当项目(列表/集合)的属性包含另一个项目时选择项目 [英] JPA JPQL: select items when attribute of item (list/set) contains another item

问题描述

public class Document extends Model {
... 
@ManyToMany
public Set<User> accessors;
...
}

我要选择访问者包含某个用户的所有文档. 我只有很少的SQL经验，而没有JPQL的经验. 那怎么办呢?

I want to select all Documents which accessors contain a certain user. I have just minimal experiences with SQL and no experiences with JPQL. So how to do that?

预先感谢

推荐答案

SELECT d FROM Document AS d WHERE :user MEMBER OF d.accessors

应该是您所需要的，并且比联接表更简单. 只是不要忘记将用户用作参数，而不是使用其ID:

Should be what you need, and it is simpler than joining tables. Just dont forget to use the user as a parameter instead of using its id:

query.setParameter("user", user);

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