在PostgreSQL中使用JPA存储库从序列中获取下一个值 [英] Getting next value from sequence with jpa repository in postgreSQL

问题描述

我已经看到了类似的问题，但是在我的情况下，它是行不通的. 我需要获取序列的下一个值.

I've seen the similar question, but in my situation it doesn't work. I need to get the next value of the sequence.

模型类:

@Entity
@Table(name = "item")
public class Item {
    @Id
    @SequenceGenerator(name = "id_seq", sequenceName = "item_id_seq", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_seq")
    @Column(name = "id", updatable = false)
    protected Long id;
}

Jpa存储库:

public interface ItemRepository extends JpaRepository<Item, Long> {
    List<Item> findFirst10ByOrderByPublicationDateDesc();

    @Query(value = "SELECT item_id_seq.nextval FROM item", nativeQuery = 
    true)
    Long getNextSeriesId();
}

我将不胜感激.

推荐答案

我找到了解决方法:

@Query(value = "SELECT nextval('item_id_seq')", nativeQuery =
            true)
    Long getNextSeriesId();

我的错误是我使用的是oracle语法而不是PostgreSQL.

My mistake was that I used oracle syntax instead of postgreSQL, which I am using.

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