jpa-将jpql联接查询转换为条件api [英] jpa - transforming jpql join query to criteria api

问题描述

我正在尝试转换此JPQL查询；

I was trying to transform this JPQL query;

SELECT s FROM QuestionSet s JOIN s.questions q WHERE q.appointedRepetition.date  < :tomorrow

与其标准api等效，这是我到目前为止所拥有的:

to its criteria api equivalent, here is what I have so far:

    DateTime tomorrow = DateTime.now().plusDays(1).withTime(0,0,0,0);

    CriteriaBuilder criteriaBuilder = JPA.em().getCriteriaBuilder();
    CriteriaQuery<QuestionSet> query = criteriaBuilder.createQuery(QuestionSet.class);
    Root<QuestionSet> root = query.from(QuestionSet.class);
    Join<QuestionSet, Question> questionJoin = root.join("questions");
    Predicate ownerCondition = criteriaBuilder.equal(root.get("owner"), owner);
    Predicate dateCondition = criteriaBuilder.lessThan(questionJoin.<DateTime>get("appointedRepetition.date"), tomorrow);

    query.where(criteriaBuilder.and(ownerCondition, dateCondition));


    List<QuestionSet> result = JPA.em().createQuery(query).getResultList();

    return result;

但是我得到了

play.api.Application$$anon$1: Execution exception[[IllegalArgumentException: Unable to resolve attribute [appointedRepetition.date] against path [null]]]

查看>如何转换JPQL带有与Criteria API等效的子查询?我在Criteria API部分中具有几乎相同的代码.

Looking at How to convert a JPQL with subquery to Criteria API equivalent? I have almost the same code in criteria api part.

@Entity
@SequenceGenerator(name = "wordlist_seq", sequenceName = "wordlist_seq")
public class QuestionSet {
  @OneToMany(cascade = CascadeType.ALL)
  private List<Question> questions;
      ...
}


@Entity
@SequenceGenerator(name = "question_seq", sequenceName = "question_seq")
@Inheritance(strategy=InheritanceType.TABLE_PER_CLASS)
public abstract class Question{
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "question_seq")
    private Long id;
        ...
}


    @OneToOne(cascade = CascadeType.ALL)
    private AppointedRepetition appointedRepetition;

推荐答案

您需要另一个联接，但我不能保证它会起作用，因为实体定义丢失或不完整，并且并非所有关系都按所述定义在您的评论中.无论如何，我会尝试这样做:

You need another join, but I can't assure it will work, because the entity definitions are either missing or incomplete, and not all relationships are defined as stated in your comment. Anyway, I would try this:

Join<Question, AppointedRepetition> repetition = questionJoin.join("appointedRepetition");
Predicate dateCondition = criteriaBuilder.lessThan(repetition.get("date"), tomorrow);

顺便说一句，我看到您正在使用joda的DateTime.我从未在JPA CriteriaBuilder中使用它，所以无法保证它能正常工作.

By the way, I see that you are using joda's DateTime. I have never used it with JPA CriteriaBuilder, so I can't assure it works.

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