OpenJPA 1.2.x使用JPQL选择树结构 [英] OpenJPA 1.2.x select tree structure using JPQL

查看:116
本文介绍了OpenJPA 1.2.x使用JPQL选择树结构的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用OpenJPA 1.2.x(JPA1).问题是我无法使用JPQL来查询树结构.

I'm using OpenJPA 1.2.x (JPA1). The problem is that I can't get on with querying tree structure using JPQL.

请参见我的实体

@NamedQueries(
         { 
           @NamedQuery(
             name="Department.getFullTree",
             query="SELECT dep FROM Department dep LEFT JOIN fetch dep.children"
           )
         }
        )
@Entity
public class Department {

    public static final Long ROOT_ID = 0L;

    @Id
    @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="DEPARTMENT_SEQ")
    @SequenceGenerator(name="DEPARTMENT_SEQ", sequenceName="DEPARTMENT_SEQ", allocationSize=1)
    @Column(name="ID")
    private Long id;

    @Column(name="PARENT_ID")
    private Long parentId;

    @ManyToOne(targetEntity = Department.class, fetch = FetchType.EAGER)
    @JoinColumn(name = "PARENT_ID")
    private Department parent;

    @Column(name="LABEL")
    private String label;

    @OneToMany(mappedBy = "parent", 
               targetEntity = Department.class, 
               fetch=FetchType.LAZY, 
               cascade = {CascadeType.PERSIST, CascadeType.ALL})
    private List<Department> children;

还有我的无状态bean方法:

And my stateless bean method:

public Department getFullTree(){
    em.createNamedQuery("Department.getFullTree").getResultList();
    Department root = em.find(Department.class, Department.ROOT_ID); 
    return root;
}

我的目标是从根开始获得完整的部门树. 我已经尝试过这种方法:

My aim is to get full department tree starting from root. I've tried this approach:

是真的吗?我正在使用DB2.并将在将来使用. 用于获取整棵树的JPA查询

Is that true? I'm using DB2. And will use it in future. JPA query for getting the whole tree

这似乎不起作用: http://www.tikalk.com/java/用jpa和休眠加载树

我尝试重复,但是遍历树时出现stackoverflow错误(根本不超过200个节点). 调试输出显示root本身具有孩子身份,因此它是圆形链接结构...

I've tried to repeat, but I get stackoverflow error while traversing tree (don't have more than 200 nodes at all). Debug output showed that root has itself as a child, so it's round-linked structure...

接下来我要尝试什么?

UPD: 这是我的遍历代码:

UPD: Here is my traverse code:

public class TreeTagHelper {

    private static final Logger LOG = LoggerFactory.getLogger(TreeTagHelper.class);

    private Department root;
    private JspWriter out;

    public TreeTagHelper(Department root, JspWriter out){
        LOG.trace("#init");
        this.root = root;
        this.out = out;
    }

    public void printTree() throws Exception{
        LOG.trace("#printTree -> start");
        out.println("<ul id=\"tree-root\"> ");      
        for(Department dep : root.getChildren()){
            printNode(dep, out);
        }       
        closeUL(out);
        LOG.trace("#printTree -> end");
    }

    public static void printNode(Department dep, JspWriter out) throws Exception{
        LOG.trace("#printNode title[{}] children.size()[{}]",dep.getLabel(), (dep.getChildren() == null ? "NULL" : dep.getChildren().size()) );
        openLI(out);
        out.print("<span id=\"tree_node_"+dep.getId()+"\" class=\"ekp-tree-node\" onclick=\"ekpCommon.tree.toggleBullet(this)\">"+dep.getLabel()+"</span>");
        if(dep.getChildren()!=null){
            openUL(out);
            for(Department child : dep.getChildren()){
                printNode(child, out);
            }
            closeUL(out);
        }

        closeLI(out);
    }

    public static void openUL(JspWriter  out) throws Exception{
        out.println("<ul>");
    }

    public static void closeUL(JspWriter out) throws Exception{
        out.println("</ul>");       
    }

    public static void openLI(JspWriter out) throws Exception{
        out.println("<li>");
    }

    public static void closeLI(JspWriter out) throws Exception{
        out.println("</li>");       
    }

LOG.trace(#printNode title [{}] children.size()[{}]",dep.getLabel(),(dep.getChildren()== null?"NULL":dep.getChildren( ).size()));

LOG.trace("#printNode title[{}] children.size()[{}]",dep.getLabel(), (dep.getChildren() == null ? "NULL" : dep.getChildren().size()) );

始终输出:#printNode标题[所有部门] children.size()[19]" 似乎根(所有部门")有19个孩子.是的,我在数据库中检查了它. 但是每个孩子都是根! 所以它是无限的结构... ???根不生孩子?它会自我获取吗?

always outputs: "#printNode title[All departments] children.size()[19]" Seems like the root("All departments") has 19 children. It's true, I checked it in my DB. But each children is the root! So it's infinite structure...??? Root doesn't get children? It fetches itself?

推荐答案

我尝试重复,但是遍历树时出现stackoverflow错误(根本不超过200个节点).调试输出显示root本身具有孩子身份,因此它是圆形链接结构...

I've tried to repeat, but I get stackoverflow error while traversing tree (don't have more than 200 nodes at all). Debug output showed that root has itself as a child, so it's round-linked structure...

那么您的数据很可能是错误的.仔细检查根是否没有父级.

Then your data are very likely wrong. Double check that the root has no parent.

这篇关于OpenJPA 1.2.x使用JPQL选择树结构的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆