Formitit/Add中的jqgrid动态表单更改标签 [英] jqgrid dynamic form change label in formedit/add
本文介绍了Formitit/Add中的jqgrid动态表单更改标签的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个表格 ....
i have a form ....
{
width:450,height:350, //1
beforeShowForm: function(formID) {
recreateForm: true,
alert("Really?") ;
jQuery('#tr_b_date', formID).show();
jQuery('#tr_buchung', formID).show();
jQuery('#tr_b_menge_lsv', formID).hide();
jQuery('#tr_b_text_lsv', formID).hide();
jQuery('#tr_b_summe_lsv', formID).hide();
jQuery('#tr_b_menge_cvvp', formID).hide();
jQuery('#tr_b_text_cvvp', formID).hide();
jQuery('#tr_b_summe_cvvp', formID).hide();
jQuery('#buchung', formID).change(function() {
var index = $(this)[0].selectedIndex;
if (index == 1) {
jQuery("#kundenbuchung").setColProp('LSV',
{formoptions:{label:'TEST1'}});
jQuery("#kundenbuchung").setColProp('Count_L',
{formoptions:{label:'TEST2'}});
jQuery('#tr_b_summe_lsv', formID).show();
jQuery('#tr_b_text_lsv', formID).show();
jQuery('#tr_b_menge_lsv', formID).hide();
jQuery('#tr_b_menge_cvvp', formID).hide();
jQuery('#tr_b_text_cvvp', formID).hide();
jQuery('#tr_b_summe_cvvp', formID).hide();
}
else if (index == 2) { .....`
我想动态更改表单中的标签,但是
I want to change the labels in the form dynamicly, but
jQuery("#kundenbuchung").setColProp('LSV', {formoptions: { label: 'TEST1' }} );
jQuery("#kundenbuchung").setColProp('Count_L',{formoptions: { label: 'TEST2' }} );
不起作用.有任何想法吗?
沙洛特
doesn't work. Any Ideas?
Schalotte
推荐答案
beforeShowForm
内部的表单已创建.您可以尝试在beforeInitData
内部更改label
.
Inside of beforeShowForm
the form is already created. You can tried to change label
inside of beforeInitData
.
另一种方法是改变
jQuery("#kundenbuchung").setColProp('LSV', {formoptions: {label:'TEST1'}})
到
jQuery('tr#tr_LSV > td.CaptionTD', formID[0]).html('TEST1')
或与此有关的东西.我建议您使用 recreateForm:true 选项作为确保在每次编辑行时都会调用beforeShowForm
.
or something about this. I recommend you to use recreateForm:true option to be sure that beforeShowForm
will be called at every row editing.
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