带有JSON数据的jqGrid将表呈现为空 [英] jqGrid with JSON data renders table as empty

问题描述

我正在尝试创建一个jqgrid，但是表为空.该表将呈现，但数据不会显示.

I'm trying to create a jqgrid, but the table is empty. The table renders, but the data doesn't show.

我从php调用中获取的数据是:

The data I'm getting back from the php call is:

{
"page":"1",
"total":1,
"records":"10",
"rows":[
{"id":"2:1","cell":["1","image","Chief Scout","Highest Award test","0"]},
{"id":"2:2","cell":["2","image","Link Badge","When you are invested as a Scout, you may be eligible to receive a Link Badge. (See page 45)","0"]},
{"id":"2:3","cell":["3","image","Pioneer Scout","Upon completion of requirements, the youth is invested as a Pioneer Scout","0"]},
{"id":"2:4","cell":["4","image","Voyageur Scout Award","Voyageur Scout Award is the right after Pioneer Scout.","0"]},
{"id":"2:5","cell":["5","image","Voyageur Citizenship","Learning about and caring for your community.","0"]},
{"id":"2:6","cell":["6","image","Fish and Wildlife","Demonstrate your knowledge and involvement in fish and wildlife management.","0"]},
{"id":"2:7","cell":["7","image","Photography","To recognize photography knowledge and skills","0"]},
{"id":"2:8","cell":["8","image","Recycling","Demonstrate your knowledge and involvement in Recycling","0"]},
{"id":"2:10","cell":["10","image","Voyageur Leadership ","Show leadership ability","0"]},
{"id":"2:11","cell":["11","image","World Conservation","World Conservation Badge","0"]}
]}

javascript配置如下:

The javascript configuration looks like so:

$("#"+tableId).jqGrid ({
    url:'getAwards.php?id='+classId,
    dataType : 'json',
    mtype:'POST',
    colNames:['Id','Badge','Name','Description',''],
    colModel : [
        {name:'awardId', width:30, sortable:true, align:'center'},
        {name:'badge', width:40, sortable:false, align:'center'},
        {name:'name', width:180, sortable:true, align:'left'},
        {name:'description', width:380, sortable:true, align:'left'},
        {name:'selected', width:0, sortable:false, align:'center'}
        ],
    sortname: "awardId",
    sortorder: "asc",
    pager: $('#'+tableId+'_pager'),
    rowNum:15,
    rowList:[15,30,50],
    caption: 'Awards',
    viewrecords:true,
    imgpath: 'scripts/jqGrid/themes/green/images',
    jsonReader : { 
        root: "rows", 
        page: "page", 
        total: "total", 
        records: "records", 
        repeatitems: true, 
        cell: "cell", 
        id: "id",
        userdata: "userdata", 
        subgrid: {root:"rows", repeatitems: true, cell:"cell" } 
    },
    width: 700,
    height: 200
});

HTML如下:

<table class="awardsList" id="awardsList2" class="scroll" name="awardsList" />
<div id="awardsList2_pager" class="scroll"></div>

我不确定是否需要定义jsonReader，因为我尝试保持默认值.如果php代码有帮助，我也可以发布.

I'm not sure that I needed to define jsonReader, since I've tried to keep to the default. If the php code will help, I can post it too.

推荐答案

我明白了！

数据类型字段应为数据类型.区分大小写.

The dataType field should be datatype. It's case sensitive.

这篇关于带有JSON数据的jqGrid将表呈现为空的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！