jqGrid拖放接收事件 [英] jqGrid drag and drop Receive event
本文介绍了jqGrid拖放接收事件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用jqgrid拖放,我有两个表TABLE A和TABLE B,我从TABLE A拖了一行,然后放入TABLE B,我想捕获新的行ID和表中接收到的数据,是否在那里jqGrid中有任何接收事件吗?
I am using jqgrid drag and drop , i have two tables TABLE A and TABLE B, i am draging one row from TABLE A and Droping into TABLE B, i Want to capture new row id and data received in table, is there any receive event in jqGrid ?
推荐答案
You can define ondrop
event function (see this Link ) like following
jQuery("#table2").jqGrid('gridDnD', {
ondrop: function (ev, ui, getdata) {
// var acceptId = $(ui.draggable).attr("id");
// getdata is the data from $('#table1').jqGrid('getRowData',acceptId);
// so you have full information about dropped row
}
});
在ondrop
参数的内部
,您将找到所需的所有信息.
inside of ondrop
's parameters you will find all information which you need.
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