如何在Jqgrid中显示嵌套的Json对象 [英] How to display nested Json object in Jqgrid

问题描述

我对jqgrid相当陌生 如何在jqgrid中将嵌套的json对象显示为单个字段? 下面给出的是json对象的示例

I'm fairly new to jqgrid How can I show nested json objects inside a jqgrid as individual fields?? below given is the example of json object

[
 {
"properties":{
 "x":1,
 "y":78093,
 "closeDate":null,
 "
},
"children":[
 {
    "properties":{

       "option":null,
       "type":"",
       "client":"southface",

       "categoryA":[
          "x",
          "w"
       ],
       "facilitiesOther":null,
       "objectId":10,

       "docNo":7897,
       "Provisions":[
          "x",
          "z"
       ],


       "sponsor":"own sponsor",


       "CategoryB":[
          "e",
          "f",
          "g"

       ]

       ]
    },
    "children":null,
    "Type":"test",
    "Id":"10"
 }
  ],
  "objectType":"document",
 "objectId":"89763"
   }
  ]

经过大量研究，我发现它需要修改colmodel 解决这个问题会很有帮助 预先感谢

after fair amount of research I found somewhere that it requires modifying the colmodel Something towards this issue would be very helpful thanks in advance

推荐答案

您应使用jsonMap.您还应该查看 jqGrid Wiki 和

You should use jsonMap. You should also look at jqGrid wiki and this specific topic. You can try something like this:

colNames:['Children','ID', 'Properties', 'Other','Sponsor'],
colModel: [
    {name:'children',width:100, jsonmap:"children.0", formatter: function (cellvalue) { return cellvalue.children }},
    {name:'objectId',width:100, jsonmap:"children.0", formatter: function (cellvalue) { return cellvalue.objectType }},
    {name:'properties',width:100, jsonmap:"children.0", formatter: function (cellvalue) { return cellvalue.properties.objectId }},
    {name:'other',width:100, jsonmap:"children.0", formatter: function (cellvalue) { return cellvalue.properties.other[0] }},
    {name:'sponsor',width:100, jsonmap:"children.0", formatter: function (cellvalue) { return cellvalue.properties.sponsor }}
    // and so on...
],

这显然不是最好的方法，因为您必须知道JSON上有多少条记录，并为每条记录手动进行.实际上，我不知道如何自动实现它，但是正如我所说，如果您在

This is obviously not the best approach because you'll have to know how many records you have on your JSON and do it manually for each one. Actually, I don't know how you could make it automatically, but as I said, if you look out for jsonMap on jqGrid wiki you'll probably find what you want. Best of luck!

这篇关于如何在Jqgrid中显示嵌套的Json对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！