JqGrid PHP:通过工具栏过滤时突出显示结果 [英] JqGrid PHP: highlight results, when filtering via toolbar
本文介绍了JqGrid PHP:通过工具栏过滤时突出显示结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
使用过滤器工具栏时,我想突出显示搜索结果.
I would like to highlight the search results, when using the filter toolbar.
我尝试使用解决方案 Oleg 和此处提供了, 但它在PHP的JqSuite中不起作用.
I tried to use the solution Oleg and Abhishek Simon provided here, but it is not working in JqSuite for PHP.
grid.php 代码段
$highlighting = <<<HIGHLIGHTING
function () {
var filters, i, l, rules, rule, iCol, $this = $(this);
if (this.p.search === true) {
filters = $.parseJSON(this.p.postData.filters);
if (filters !== null && typeof filters.rules !== 'undefined' &&
filters.rules.length > 0) {
rules = filters.rules;
l = rules.length;
for (i = 0; i < l; i++) {
rule = rules[i];
iCol = getColumnIndexByName($this, rule.field);
if (iCol >=0) {
$('>tbody>tr.jqgrow>td:nth-child(' + (iCol + 1) +
')', this).highlight(rule.data);
}
}
}
}
}
HIGHLIGHTING;
$grid->setGridEvent('loadComplete',$highlighting);
我收到此错误:
注意:未定义的变量:此
你能弄错我在做什么吗?
Are you able to get what I am doing wrong?
推荐答案
我自己不使用PHP.无论如何,您应该知道您在页面上使用的网格的ID.例如,如果是id="grid"
,则可以在函数代码内用$("#grid")[0]
替换this
.
I don't use PHP myself. Anyway you should know the ID of the grid which you use on the page. If it is for example id="grid"
then you can replace this
with $("#grid")[0]
inside of the code of the function.
这篇关于JqGrid PHP:通过工具栏过滤时突出显示结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文