Jqgrid,带有用于Json返回的参数的调用URL [英] Jqgrid, call URL with parameters for Json return
问题描述
我在aspx页面上有以下代码:
i have the following code on my aspx page:
jQuery("#listFondos").jqGrid({
url: '/PorMyController/LoadGridData/',
datatype: 'json',
mtype: 'GET',
colNames: ['col1', 'col2',...etc
一切正常,但是我想知道是否可以调用发送一些参数的URL方法.我知道默认情况下,当您调用url方法时,jqgrid发送一些参数来控制网格的分页:
Everything is working fine, but i'm wondering if is it possible to call the URL method sending some parameters. I know that by default, when you call the url method, jqgrid sends some parameters to control paging of the grid:
public ActionResult LoadGridData(string sidx, string sord, int page, int rows)
因此,我想添加一个额外的参数,以对要加载到网格中的数据进行一些过滤.例如,我想拥有这个:
So, i want to add an extra parameter to make some filter on the data that is going to be loaded into the grid. For example i would like to have this:
public ActionResult LoadGridData(string sidx, string sord, int page, int rows, string filterId)
据我所知,我不需要指定前3个参数,因为默认情况下jqgrid会这样做,但是如何发送filterId参数?
As i know, i don't need to specify the first 3 parameters, cause jqgrid does it by default, but how do i send the filterId parameter?
推荐答案
我自己解决了这个问题. 所有需要做的就是将参数作为查询字符串发送到url上:
I solve the problem myself. All that is needed to do is send the parameter as querystring on the url:
url: '/PorMyController/LoadGridData?filterId=123',...etc
用于分页的默认参数将继续发送,因此您只需指定其他参数即可.
The defaul parameters for paging will keep being sended, so you only have to specify the additional parameters.
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