jqGrid:搜索框:如何以编程方式隐藏搜索弹出窗口 [英] jqGrid: Search Box: How to hide the search popup programmatically

问题描述

我正在使用jqGrid插件及其高级搜索"功能.有没有办法以编程方式显示/隐藏搜索弹出窗口?我想根据屏幕上其他位置的用户操作来隐藏弹出窗口(如果当前正在显示).

I'm using the jqGrid plugin along with its 'advanced search' feature. Is there a way to programmatically show/hide the search popup? I'd like to hide the popup, if it's currently being displayed, based upon a user action elsewhere on the screen.

推荐答案

如果您的jqGrid具有id="list"，则高级搜索"对话框将具有id="fbox_list"
(它将通过"fbox_"前缀和网格的ID构建).因此，要隐藏该对话框，应该足以使用:

If you have a jqGrid with id="list" then the "Advanced Search" dialog will have id="fbox_list"
(it will be build from the "fbox_" prefix and the grid's id). So, to hide the dialog it should be enough to use:

$("#fbox_list").hide();

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