上传图片HTTP POST的Andr​​oid [英] Upload Image HTTP POST Android

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本文介绍了上传图片HTTP POST的Andr​​oid的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在Android和有问题的android上传影像新手。我已经试图找到例子,但有没有运气:

我有错误说:


  


和这里是我的code:
我已经阵列名为图像它包含了我要上传图片的路径
例如/storage/sdcard0/DCIM/Camera/IMG_20131214_171438.jpg

  // ONCLICK LISTENER
公共OnClickListener upload_image =新OnClickListener(){            @覆盖
            公共无效的onClick(视图v){
                // TODO自动生成方法存根
                如果(images.size()!= 0){                    。StrictMode.ThreadPolicy政策=新StrictMode.ThreadPolicy.Builder()permitAll()建();
                    StrictMode.setThreadPolicy(政策);                    的for(int i = 0; I< images.size();我++){
                        doFileUpload(images.get(I));
                    }
                }
            }
        };

// UPLOAD

 私人无效doFileUpload(字符串upload_file){
                Log.d(目前排队,upload_file);
                HttpURLConnection的康恩= NULL;
                DataOutputStream类DOS = NULL;
                DataInputStream以inStream中= NULL;
                字符串exsistingFileName = upload_file;
                //这是这个地方,你做错了什么。
                字符串lineEnd =\\ r \\ n;
                串twoHyphens = - ;
                字符串边界=acebdf13572468;
                INT读取动作,方bytesAvailable,缓冲区大小;
                字节[]缓冲区;
                INT MAXBUFFERSIZE = 1 * 1024 * 1024;
                字符串urlString =htt​​p://test.xponlm.com/MobileServices/api/ShipmentImages;
                尝试
                {
                    Log.e(MediaPlayer的,内部第二种方法);
                    的FileInputStream的FileInputStream =新的FileInputStream(新文件(exsistingFileName));
                    网址URL =新的URL(urlString);
                    康恩=(HttpURLConnection类)url.openConnection();
                    conn.setDoInput(真);
                    //允许输出
                    conn.setDoOutput(真);
                    //不要使用缓存副本。
                    conn.setUseCaches(假);
                    //使用POST方法。
                    conn.setRequestMethod(POST);
                    conn.setRequestProperty(连接,保持活动);
                    conn.setRequestProperty(内容类型,的multipart / form-data的;边界=+边界);
                    DOS =新的DataOutputStream类(conn.getOutputStream());
                    dos.writeBytes(twoHyphens +边界+ lineEnd);
                    dos.writeBytes(内容处置:表格数据;名称= \\UploadedFile的\\;文件名= \\+ exsistingFileName +\\+ lineEnd);
                    dos.writeBytes(lineEnd);                    dos.writeBytes(twoHyphens +边界+ lineEnd);
                    dos.writeBytes(内容处置:表格数据;名称= \\ID \\+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes(strshipmentID + lineEnd);                    dos.writeBytes(twoHyphens +边界+ lineEnd);
                    dos.writeBytes(内容处置:表格数据;名称= \\将ImageType \\+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes(JPG+ lineEnd);                    dos.writeBytes(twoHyphens +边界+ lineEnd);
                    dos.writeBytes(内容处置:表格数据;名称= \\文件类型\\+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes(strtype + lineEnd);                    Log.e(MediaPlayer的,头信息);
                    参考bytesAvailable = fileInputStream.available();
                    BUFFERSIZE = Math.min(方bytesAvailable,MAXBUFFERSIZE);
                    缓冲区=新的字节[缓冲区大小]
                    读取动作= fileInputStream.read(缓冲液,0,缓冲区大小);                    而(读取动作大于0){
                        dos.write(缓冲液,0,缓冲区大小);
                        参考bytesAvailable = fileInputStream.available();
                        BUFFERSIZE = Math.min(方bytesAvailable,MAXBUFFERSIZE);
                        读取动作= fileInputStream.read(缓冲液,0,缓冲区大小);
                    }                    dos.writeBytes(lineEnd);
                    dos.writeBytes(twoHyphens +边界+ twoHyphens + lineEnd);
                    在的BufferedReader =新的BufferedReader(新的InputStreamReader(conn.getInputStream()));
                    串inputLine;
                    而((inputLine = in.readLine())!= NULL)
// tv.append(inputLine);
                        Log.d(inputLine,inputLine);
                    //关闭流
                    Log.e(MediaPlayer的,文件写入);
                    fileInputStream.close();
                    dos.flush();
                    dos.close();
                }
                赶上(MalformedURLException的前)
                {
                    Log.e(MediaPlayer的,ERROR1:+ ex.getMessage(),除息);
                }
                赶上(IOException异常IOE)
                {
                    Log.e(MediaPlayer的,误差2:+ ioe.getMessage(),IOE);
                }                // ------------------读取服务器响应
                尝试{
                    inStream中=新DataInputStream所(conn.getInputStream());
                    字符串str;                    而((海峡= inStream.readLine())!= NULL){
                        Log.e(MediaPlayer的,服务器响应+ STR);
                    }
                    / *而((海峡= inStream.readLine())!= NULL){                    } * /
                    inStream.close();
                }
                赶上(IOException异常ioex){
                    Log.e(MediaPlayer的,误差3:+ ioex.getMessage(),ioex);
                }
            }

难道我错过了财产以后?你能告诉什么是对我的code中的问题?


解决方案

 公开文件上传(字符串URL,字符串userid,
            字符串文件路径,字符串状态){
        HttpClient的HttpClient的=新DefaultHttpClient();
        HttpPost httppost =新HttpPost(URL);
        MultipartEntity实体=新MultipartEntity(
                HttpMultipartMode.BROWSER_COMPATIBLE);
        的HttpParams的HttpParams = httpclient.getParams();
        httpParams.setIntParameter(CoreConnectionPNames.SO_TIMEOUT,100000);
        尝试{
            entity.addPart(键1
                    新StringBody(用户ID,Charset.forName(UTF-8)));
            entity.addPart(键2,
                    新StringBody(状态,Charset.forName(UTF-8)));
            entity.addPart(文件,新FileBody(新文件(文件路径)));
            httppost.setEntity(实体);
            ResponseHandler所<串GT; ResponseHandler所=新BasicResponseHandler();
            字符串的响应= httpclient.execute(httppost,ResponseHandler所);        }赶上(例外五){        }
    }

I'm newbie in android and having problem uploading image in android. I'd already tried to find examples but got no luck:

I am having error saying:

and here is my code: I have Array named "images" which contains the paths of images that I want to upload e.g. /storage/sdcard0/DCIM/Camera/IMG_20131214_171438.jpg

//ONCLICK LISTENER    
public OnClickListener upload_image = new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                if(images.size() != 0) {

                    StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
                    StrictMode.setThreadPolicy(policy);

                    for(int i=0; i<images.size(); i++){
                        doFileUpload(images.get(i));
                    }
                }
            }
        };

//UPLOAD

private void doFileUpload(String upload_file){
                Log.d("Currently queued", upload_file);
                HttpURLConnection conn = null;
                DataOutputStream dos = null;
                DataInputStream inStream = null;
                String exsistingFileName = upload_file;
                // Is this the place are you doing something wrong.
                String lineEnd = "\r\n";
                String twoHyphens = "--";
                String boundary =  "acebdf13572468";
                int bytesRead, bytesAvailable, bufferSize;
                byte[] buffer;
                int maxBufferSize = 1*1024*1024;
                String urlString = "http://test.xponlm.com/MobileServices/api/ShipmentImages";
                try
                {
                    Log.e("MediaPlayer","Inside second Method");
                    FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
                    URL url = new URL(urlString);
                    conn = (HttpURLConnection) url.openConnection();
                    conn.setDoInput(true);
                    // Allow Outputs
                    conn.setDoOutput(true);
                    // Don't use a cached copy.
                    conn.setUseCaches(false);
                    // Use a post method.
                    conn.setRequestMethod("POST");
                    conn.setRequestProperty("Connection", "Keep-Alive");
                    conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
                    dos = new DataOutputStream( conn.getOutputStream() );
                    dos.writeBytes(twoHyphens + boundary + lineEnd);
                    dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
                    dos.writeBytes(lineEnd);

                    dos.writeBytes(twoHyphens + boundary + lineEnd);
                    dos.writeBytes("Content-Disposition: form-data; name=\"ID\""+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes(strshipmentID + lineEnd);

                    dos.writeBytes(twoHyphens + boundary + lineEnd);
                    dos.writeBytes("Content-Disposition: form-data; name=\"ImageType\""+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes("JPG" + lineEnd);

                    dos.writeBytes(twoHyphens + boundary + lineEnd);
                    dos.writeBytes("Content-Disposition: form-data; name=\"FileType\""+ lineEnd);
                    dos.writeBytes(lineEnd);
                    dos.writeBytes(strtype + lineEnd);

                    Log.e("MediaPlayer","Headers are written");
                    bytesAvailable = fileInputStream.available();
                    bufferSize = Math.min(bytesAvailable, maxBufferSize);
                    buffer = new byte[bufferSize];
                    bytesRead = fileInputStream.read(buffer, 0, bufferSize);

                    while (bytesRead > 0) {
                        dos.write(buffer, 0, bufferSize);
                        bytesAvailable = fileInputStream.available();
                        bufferSize = Math.min(bytesAvailable, maxBufferSize);
                        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
                    }

                    dos.writeBytes(lineEnd);
                    dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
                    BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
                    String inputLine;
                    while ((inputLine = in.readLine()) != null)
//                      tv.append(inputLine);
                        Log.d("inputLine", inputLine);
                    // close streams
                    Log.e("MediaPlayer","File is written");
                    fileInputStream.close();
                    dos.flush();
                    dos.close();
                }
                catch (MalformedURLException ex)
                {
                    Log.e("MediaPlayer", "error1: " + ex.getMessage(), ex);
                }
                catch (IOException ioe)
                {
                    Log.e("MediaPlayer", "error2: " + ioe.getMessage(), ioe);
                }

                //------------------ read the SERVER RESPONSE
                try {
                    inStream = new DataInputStream ( conn.getInputStream() );
                    String str;            

                    while (( str = inStream.readLine()) != null) {
                        Log.e("MediaPlayer","Server Response"+str);
                    }
                    /*while((str = inStream.readLine()) !=null ){

                    }*/
                    inStream.close();
                }
                catch (IOException ioex){
                    Log.e("MediaPlayer", "error3: " + ioex.getMessage(), ioex);
                }
            }

Did I missed somthing? Can you tell what is the problem on my code?

解决方案

public Fileupload(String url, String userid,
            String filepath, String status) {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        MultipartEntity entity = new MultipartEntity(
                HttpMultipartMode.BROWSER_COMPATIBLE);
        HttpParams httpParams = httpclient.getParams();
        httpParams.setIntParameter(CoreConnectionPNames.SO_TIMEOUT, 100000);
        try {
            entity.addPart("key 1",
                    new StringBody(userid, Charset.forName("UTF-8")));
            entity.addPart("key 2",
                    new StringBody(status, Charset.forName("UTF-8")));
            entity.addPart("File ", new FileBody(new File(filepath)));
            httppost.setEntity(entity);
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            String response = httpclient.execute(httppost, responseHandler);

        } catch (Exception e) {

        }
    }

这篇关于上传图片HTTP POST的Andr​​oid的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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