上传图片HTTP POST的Android [英] Upload Image HTTP POST Android
本文介绍了上传图片HTTP POST的Android的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在Android和有问题的android上传影像新手。我已经试图找到例子,但有没有运气:
我有错误说:
块引用>和这里是我的code:
我已经阵列名为图像
它包含了我要上传图片的路径
例如/storage/sdcard0/DCIM/Camera/IMG_20131214_171438.jpg// ONCLICK LISTENER
公共OnClickListener upload_image =新OnClickListener(){ @覆盖
公共无效的onClick(视图v){
// TODO自动生成方法存根
如果(images.size()!= 0){ 。StrictMode.ThreadPolicy政策=新StrictMode.ThreadPolicy.Builder()permitAll()建();
StrictMode.setThreadPolicy(政策); 的for(int i = 0; I< images.size();我++){
doFileUpload(images.get(I));
}
}
}
};// UPLOAD
私人无效doFileUpload(字符串upload_file){
Log.d(目前排队,upload_file);
HttpURLConnection的康恩= NULL;
DataOutputStream类DOS = NULL;
DataInputStream以inStream中= NULL;
字符串exsistingFileName = upload_file;
//这是这个地方,你做错了什么。
字符串lineEnd =\\ r \\ n;
串twoHyphens = - ;
字符串边界=acebdf13572468;
INT读取动作,方bytesAvailable,缓冲区大小;
字节[]缓冲区;
INT MAXBUFFERSIZE = 1 * 1024 * 1024;
字符串urlString =http://test.xponlm.com/MobileServices/api/ShipmentImages;
尝试
{
Log.e(MediaPlayer的,内部第二种方法);
的FileInputStream的FileInputStream =新的FileInputStream(新文件(exsistingFileName));
网址URL =新的URL(urlString);
康恩=(HttpURLConnection类)url.openConnection();
conn.setDoInput(真);
//允许输出
conn.setDoOutput(真);
//不要使用缓存副本。
conn.setUseCaches(假);
//使用POST方法。
conn.setRequestMethod(POST);
conn.setRequestProperty(连接,保持活动);
conn.setRequestProperty(内容类型,的multipart / form-data的;边界=+边界);
DOS =新的DataOutputStream类(conn.getOutputStream());
dos.writeBytes(twoHyphens +边界+ lineEnd);
dos.writeBytes(内容处置:表格数据;名称= \\UploadedFile的\\;文件名= \\+ exsistingFileName +\\+ lineEnd);
dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens +边界+ lineEnd);
dos.writeBytes(内容处置:表格数据;名称= \\ID \\+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(strshipmentID + lineEnd); dos.writeBytes(twoHyphens +边界+ lineEnd);
dos.writeBytes(内容处置:表格数据;名称= \\将ImageType \\+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(JPG+ lineEnd); dos.writeBytes(twoHyphens +边界+ lineEnd);
dos.writeBytes(内容处置:表格数据;名称= \\文件类型\\+ lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(strtype + lineEnd); Log.e(MediaPlayer的,头信息);
参考bytesAvailable = fileInputStream.available();
BUFFERSIZE = Math.min(方bytesAvailable,MAXBUFFERSIZE);
缓冲区=新的字节[缓冲区大小]
读取动作= fileInputStream.read(缓冲液,0,缓冲区大小); 而(读取动作大于0){
dos.write(缓冲液,0,缓冲区大小);
参考bytesAvailable = fileInputStream.available();
BUFFERSIZE = Math.min(方bytesAvailable,MAXBUFFERSIZE);
读取动作= fileInputStream.read(缓冲液,0,缓冲区大小);
} dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens +边界+ twoHyphens + lineEnd);
在的BufferedReader =新的BufferedReader(新的InputStreamReader(conn.getInputStream()));
串inputLine;
而((inputLine = in.readLine())!= NULL)
// tv.append(inputLine);
Log.d(inputLine,inputLine);
//关闭流
Log.e(MediaPlayer的,文件写入);
fileInputStream.close();
dos.flush();
dos.close();
}
赶上(MalformedURLException的前)
{
Log.e(MediaPlayer的,ERROR1:+ ex.getMessage(),除息);
}
赶上(IOException异常IOE)
{
Log.e(MediaPlayer的,误差2:+ ioe.getMessage(),IOE);
} // ------------------读取服务器响应
尝试{
inStream中=新DataInputStream所(conn.getInputStream());
字符串str; 而((海峡= inStream.readLine())!= NULL){
Log.e(MediaPlayer的,服务器响应+ STR);
}
/ *而((海峡= inStream.readLine())!= NULL){ } * /
inStream.close();
}
赶上(IOException异常ioex){
Log.e(MediaPlayer的,误差3:+ ioex.getMessage(),ioex);
}
}难道我错过了财产以后?你能告诉什么是对我的code中的问题?
解决方案公开文件上传(字符串URL,字符串userid,
字符串文件路径,字符串状态){
HttpClient的HttpClient的=新DefaultHttpClient();
HttpPost httppost =新HttpPost(URL);
MultipartEntity实体=新MultipartEntity(
HttpMultipartMode.BROWSER_COMPATIBLE);
的HttpParams的HttpParams = httpclient.getParams();
httpParams.setIntParameter(CoreConnectionPNames.SO_TIMEOUT,100000);
尝试{
entity.addPart(键1
新StringBody(用户ID,Charset.forName(UTF-8)));
entity.addPart(键2,
新StringBody(状态,Charset.forName(UTF-8)));
entity.addPart(文件,新FileBody(新文件(文件路径)));
httppost.setEntity(实体);
ResponseHandler所<串GT; ResponseHandler所=新BasicResponseHandler();
字符串的响应= httpclient.execute(httppost,ResponseHandler所); }赶上(例外五){ }
}I'm newbie in android and having problem uploading image in android. I'd already tried to find examples but got no luck:
I am having error saying:
and here is my code: I have Array named
"images"
which contains the paths of images that I want to upload e.g. /storage/sdcard0/DCIM/Camera/IMG_20131214_171438.jpg//ONCLICK LISTENER public OnClickListener upload_image = new OnClickListener() { @Override public void onClick(View v) { // TODO Auto-generated method stub if(images.size() != 0) { StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build(); StrictMode.setThreadPolicy(policy); for(int i=0; i<images.size(); i++){ doFileUpload(images.get(i)); } } } };
//UPLOAD
private void doFileUpload(String upload_file){ Log.d("Currently queued", upload_file); HttpURLConnection conn = null; DataOutputStream dos = null; DataInputStream inStream = null; String exsistingFileName = upload_file; // Is this the place are you doing something wrong. String lineEnd = "\r\n"; String twoHyphens = "--"; String boundary = "acebdf13572468"; int bytesRead, bytesAvailable, bufferSize; byte[] buffer; int maxBufferSize = 1*1024*1024; String urlString = "http://test.xponlm.com/MobileServices/api/ShipmentImages"; try { Log.e("MediaPlayer","Inside second Method"); FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) ); URL url = new URL(urlString); conn = (HttpURLConnection) url.openConnection(); conn.setDoInput(true); // Allow Outputs conn.setDoOutput(true); // Don't use a cached copy. conn.setUseCaches(false); // Use a post method. conn.setRequestMethod("POST"); conn.setRequestProperty("Connection", "Keep-Alive"); conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); dos = new DataOutputStream( conn.getOutputStream() ); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd); dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"ID\""+ lineEnd); dos.writeBytes(lineEnd); dos.writeBytes(strshipmentID + lineEnd); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"ImageType\""+ lineEnd); dos.writeBytes(lineEnd); dos.writeBytes("JPG" + lineEnd); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"FileType\""+ lineEnd); dos.writeBytes(lineEnd); dos.writeBytes(strtype + lineEnd); Log.e("MediaPlayer","Headers are written"); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); buffer = new byte[bufferSize]; bytesRead = fileInputStream.read(buffer, 0, bufferSize); while (bytesRead > 0) { dos.write(buffer, 0, bufferSize); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); bytesRead = fileInputStream.read(buffer, 0, bufferSize); } dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream())); String inputLine; while ((inputLine = in.readLine()) != null) // tv.append(inputLine); Log.d("inputLine", inputLine); // close streams Log.e("MediaPlayer","File is written"); fileInputStream.close(); dos.flush(); dos.close(); } catch (MalformedURLException ex) { Log.e("MediaPlayer", "error1: " + ex.getMessage(), ex); } catch (IOException ioe) { Log.e("MediaPlayer", "error2: " + ioe.getMessage(), ioe); } //------------------ read the SERVER RESPONSE try { inStream = new DataInputStream ( conn.getInputStream() ); String str; while (( str = inStream.readLine()) != null) { Log.e("MediaPlayer","Server Response"+str); } /*while((str = inStream.readLine()) !=null ){ }*/ inStream.close(); } catch (IOException ioex){ Log.e("MediaPlayer", "error3: " + ioex.getMessage(), ioex); } }
Did I missed somthing? Can you tell what is the problem on my code?
解决方案public Fileupload(String url, String userid, String filepath, String status) { HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(url); MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE); HttpParams httpParams = httpclient.getParams(); httpParams.setIntParameter(CoreConnectionPNames.SO_TIMEOUT, 100000); try { entity.addPart("key 1", new StringBody(userid, Charset.forName("UTF-8"))); entity.addPart("key 2", new StringBody(status, Charset.forName("UTF-8"))); entity.addPart("File ", new FileBody(new File(filepath))); httppost.setEntity(entity); ResponseHandler<String> responseHandler = new BasicResponseHandler(); String response = httpclient.execute(httppost, responseHandler); } catch (Exception e) { } }
这篇关于上传图片HTTP POST的Android的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文