出生日期验证持续显示 [英] Date of Birth validation keeps showing

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本文介绍了出生日期验证持续显示的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在文本框中输入DOB-22/12/1986,验证一直有效.它说:

I am typing a DOB - 22/12/1986 into my text box and the validation keeps firing. It says:

The field DOB must be a date.

我的模型:

[System.ComponentModel.DisplayName("DOB")]
[DisplayFormat(DataFormatString = "@{0:dd/MM/yyyy}", ApplyFormatInEditMode = true)]
[Required(ErrorMessage = "Date Of Birth is required")]
[RegularExpression(@"{0:dd/MM/yyyy}", ErrorMessage = "Invalid Date")] // below is a link
public DateTime DOB { get; set; }

我的查看:

<div class="form-group">
    @Html.LabelFor(model => model.DOB, htmlAttributes: new { @class = "control-label col-md-2" })
    <div class="col-md-10">
        @Html.EditorFor(model => model.DOB, new { htmlAttributes = new { @class = "form-control" } })
        @Html.ValidationMessageFor(model => model.DOB, "", new { @class = "text-danger" })
    </div>
</div>

MS SQL database中,该字段为:DateTime

为什么我的验证说我输入的日期无效?

Why does my validation say that the date i type in is invalid?

推荐答案

进行客户端验证的原因是,jquery.validate.unobtrusive.js使用的jquery.validate.js插件根据MM/dd/yyyy格式验证日期,并根据dd/MM/yyyy格式.

The reason for the client side validation is that the jquery.validate.js plugin used by jquery.validate.unobtrusive.js validates dates based on MM/dd/yyyy format and your entering dates based on a dd/MM/yyyy format.

jquery.validate.js中用于验证的特定代码是

The specific code used in jquery.validate.js for validation is

date: function(value, element) {
    return this.optional(element) || !/Invalid|NaN/.test(new Date(value));
}

这取决于您使用的浏览器会给出不同的结果(在Chrome中,new Date('22/12/1986')返回Invalid Date,但是在FireFox中,它返回有效的1987-10-11T13:30:00.000Z,只是您输入的日期无效)

which depending on the browser your using will give different results (in Chrome, new Date('22/12/1986') returns Invalid Date but in FireFox it returns 1987-10-11T13:30:00.000Zwhich is valid, just not the date you entered)

您需要覆盖$.validator才能设置区域性格式的日期.一种选择是使用 jquery.globalize 插件.

You need to override the $.validator to format dates in your culture. One option is to use the jquery.globalize plugin.

或者,您可以编写自己的脚本.请注意,以下脚本取自我自己的插件,该插件与生成日期选择器的@Html.DatePickerFor()扩展方法结合使用.扩展方法基于服务器区域性为日期格式添加html属性,并使用我已注释掉并用您的硬编码格式替换的var format = regex.exec(this.inputFormat);代码行读取.如果您只想使用dd/MM/yyyy格式,则可以简化脚本,因为您只需要'little-endian'格式

Alternatively you can write your own script. Note that the following script is taken from my own plugin used in conjunction with a @Html.DatePickerFor() extension method that generates a datepicker. The extension method adds html attributes for the date format based on the server culture and is read with the var format = regex.exec(this.inputFormat); line of code that I have commented out and replaced with your hard coded format. If you only ever want the dd/MM/yyyy format, then the script can be simplified because you only need the 'little-endian' format

<script type="text/javascript">
    // Override default date validator format to allow culture specific format
    $.validator.methods.date = function (value, element) {
        return this.optional(element) || globalDate(value).isValid();
    };

    globalDate = function (value) {
        // Initialise a new date
        var date = new Date(0);
        if (value == undefined) {
            // Return todays date
            return date;
        }
        // Get the components of the format
        // The separator can be forward slash, hyphen, dot and/or space
        var regex = new RegExp(/([dMy]+)([\s/.-]+)([dMy]+)([\s/.-]+)([dMy]+)/);
//------------- see notes above
        //var format = regex.exec(this.inputFormat);
        var format = regex.exec('dd/MM/yyyy');
//------------- 
        // Get the components of the value
        regex = new RegExp(/(\d+)([\s/.-]+)(\d+)([\s/.-]+)(\d+)/);
        value = regex.exec(value);
        // Check the value is valid
        if (value === null || value[2] !== format[2] || value[4] !== format[4]) {
            // Its not valid
            date.setTime(Number.NaN);
            return date;
        }
        // TODO: What if year entered as 2 digits?
        var day = Number.NaN;
        var month = Number.NaN;
        var year = Number.NAN;
        if (format[1].charAt(0) === 'd') {
            // little-endian (day, month, year)
            day = parseInt(value[1]);
            month = parseInt(value[3]) - 1;
            year = parseInt(value[5]);
        } else if (format[1].charAt(0) === 'M') {
            // middle-endian (month, day, year)
            day = parseInt(value[3]);
            month = parseInt(value[1]) - 1;
            year = parseInt(value[5]);
        } else {
            // big endian (year, month, day)
            day = parseInt(value[5]);
            month = parseInt(value[3]) - 1;
            year = parseInt(value[1]);
        }
        date.setFullYear(year);
        date.setMonth(month);
        date.setDate(day);
        // Check its valid
        if (date.getDate() !== day || date.getMonth() !== month || date.getFullYear() !== year) {
            date.setTime(Number.NaN);
            return date;
        }
        return date;
    }

    // Methods 
    Date.prototype.isValid = function () {
        return !isNaN(this.getTime());
    }
</script>

旁注:您的[RegularExpression]属性不执行任何操作,可以将其删除.

Side note: Your [RegularExpression] attribute does nothing and can be removed.

这篇关于出生日期验证持续显示的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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