如何在jstree中获取所有检查的节点? [英] How to get all checked nodes in jstree?

问题描述

我需要这样导出节点:

function recursive_simplify(node){ 
    if(node.children){
        for(var i =0;i<node.children.length;i++){
            node.children[i] = recursive_simplify(node.children[i])
        }
    }
    delete node['metadata'];
    return node
}

$('body').on('click','.data-export', function () {
    var tree=$.jstree._reference('#reference-data-exchange');
    var checked = tree.get_checked(); 
    var result = [];
    for(var i=0, checkedLength = checked.length; i<checkedLength;i++)
    {
      var checkedJson = tree.get_json(checked[i],['id','rel','data-bin','data-pos'])[0];
      checkedJson = recursive_simplify(checkedJson);
      result.push(checkedJson);
    }
    alert(JSON.stringify(result));
});

一切正常，但是！我需要所有选中的节点(选中和未确定) 我的代码只返回检查. 请帮助.

it's works fine, BUT! I need all checked nodes(checked & undetermined) My code returns only checked. Plz help.

推荐答案

get_all_checked: function(obj)
           {
                obj = !obj || obj === -1 ? this.get_container() : this._get_node(obj);
                return obj.find(".jstree-checked, .jstree-undetermined");
            };

使用:

var checkedNodes = $(this).jstree("get_all_checked");

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