Android的org.apache.http.client.Htt presponseException：未找到 [英] Android org.apache.http.client.HttpResponseException: Not Found

问题描述

在我的应用我将用户信息发送到服务器以http如下，我得到的 org.apache.http.client.Htt presponseException：未找到，我有花更多的时间，但能不solution.please帮我找出解决方案。

我在这行得到错误：

jsonResponse = httpClient.execute（httpPost，resHandler）;

 公共字符串addNewCardDetail（字符串loggedin_id，FN字符串，字符串LN，
        字符串cardholdername，字符串cardno，CVV字符串，字符串EXPDATE，字符串添加，
        字符串的状态，城市的字符串，字符串针code）{    jsonResponse =;    HttpClient的=新DefaultHttpClient（）;
    resHandler =新BasicResponseHandler（）;
    httpPost =新HttpPost（HTTP：//xxx.xxx.xxx.xx/users/createCustomerCardAddress）;
    namevaluepairs中=新的ArrayList＆LT;＆的NameValuePair GT;（11）;    nameValuePairs.add（新BasicNameValuePair（loggedin_id，loggedin_id））;
    nameValuePairs.add（新BasicNameValuePair（名字，FN））;
    nameValuePairs.add（新BasicNameValuePair（姓氏，LN））;
    nameValuePairs.add（新BasicNameValuePair（cardHolderName，cardholdername））;
    nameValuePairs.add（新BasicNameValuePair（cardNumber，cardno））;
    nameValuePairs.add（新BasicNameValuePair（cardCvvCVV））;
    nameValuePairs.add（新BasicNameValuePair（EXPDATE，EXPDATE））;
    nameValuePairs.add（新BasicNameValuePair（地址，加））;
    nameValuePairs.add（新BasicNameValuePair（国家，状态））;
    nameValuePairs.add（新BasicNameValuePair（城市，市））;
    nameValuePairs.add（新BasicNameValuePair（销code，针code））;    Log.e（----------，---------）;
    的for（int i = 0; I＆LT; nameValuePairs.size（）;我++）{
        Log.e（添加/编辑新卡，nameValuePairs.get（I）.getName（））;
        Log.e（添加/编辑新卡，nameValuePairs.get（I）.getValue（））;
    }
    Log.e（----------，---------）;    尝试{
        httpPost.setEntity（新UrlEn codedFormEntity（namevaluepairs中））;
        jsonResponse = httpClient.execute（httpPost，resHandler）; //我得到org.apache.http.client.Htt presponseException：未找到
        Log.e（添加编辑卡响应， - + jsonResponse）;
    }赶上（UnsupportedEncodingException五）{
        e.printStackTrace（）;
    }赶上（ClientProtocolException E）{
        e.printStackTrace（）;
    }赶上（IOException异常五）{
        e.printStackTrace（）;
    }
    返回jsonResponse;
}
 

我的日志跟踪：

  org.apache.http.client.Htt presponseException：未找到
在org.apache.http.impl.client.BasicResponseHandler.handleResponse（BasicResponseHandler.java:71）
在org.apache.http.impl.client.BasicResponseHandler.handleResponse（BasicResponseHandler.java:59）
在org.apache.http.impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:773）
在org.apache.http.impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:743）
在org.apache.http.impl.client.AbstractHttpClient.execute（AbstractHttpClient.java:732）
在com.fssd.spot.parser.ParsorClass.addNewCardDetail（ParsorClass.java:1098）
在com.fssd.spot.payment.BillingAddress $ AddNewcard.doInBackground（BillingAddress.java:146）
在com.fssd.spot.payment.BillingAddress $ AddNewcard.doInBackground（BillingAddress.java:1）
在android.os.AsyncTask $ 2.call（AsyncTask.java:287）
在java.util.concurrent.FutureTask中$ Sync.innerRun（FutureTask.java:305）
在java.util.concurrent.FutureTask.run（FutureTask.java:137）
在android.os.AsyncTask $ SerialExecutor $ 1.run（AsyncTask.java:230）
在java.util.concurrent.ThreadPoolExecutor.runWorker（ThreadPoolExecutor.java:1076）
在java.util.concurrent.ThreadPoolExecutor中的$ Worker.run（ThreadPoolExecutor.java:569）
在java.lang.Thread.run（Thread.java:856）
 

解决方案

给出的API是无效的，这样我得到这个例外。现在我得到有效的API和工作。谢谢你。

In my app I send user information to server with http as follows, I get org.apache.http.client.HttpResponseException: Not Found and I have spend more time but could not solution.please help me find out the solution.

I get error at this line:

jsonResponse = httpClient.execute(httpPost, resHandler);

public String addNewCardDetail(String loggedin_id, String fn, String ln,
        String cardholdername, String cardno,String cvv, String expdate, String add,
        String state, String city, String pincode) {

    jsonResponse = "";

    httpClient = new DefaultHttpClient();
    resHandler = new BasicResponseHandler();
    httpPost = new HttpPost("http://xxx.xxx.xxx.xx/users/createCustomerCardAddress");
    nameValuePairs = new ArrayList<NameValuePair>(11);

    nameValuePairs.add(new BasicNameValuePair("loggedin_id",loggedin_id));
    nameValuePairs.add(new BasicNameValuePair("firstname",fn));
    nameValuePairs.add(new BasicNameValuePair("lastname",ln));
    nameValuePairs.add(new BasicNameValuePair("cardHolderName",cardholdername));
    nameValuePairs.add(new BasicNameValuePair("cardNumber",cardno));
    nameValuePairs.add(new BasicNameValuePair("cardCvv",cvv));
    nameValuePairs.add(new BasicNameValuePair("expDate",expdate));
    nameValuePairs.add(new BasicNameValuePair("address",add));
    nameValuePairs.add(new BasicNameValuePair("state",state));
    nameValuePairs.add(new BasicNameValuePair("city",city));
    nameValuePairs.add(new BasicNameValuePair("pincode",pincode));

    Log.e("----------", "---------");
    for (int i = 0; i < nameValuePairs.size(); i++) {
        Log.e("add / edit new card", nameValuePairs.get(i).getName());
        Log.e("add / edit new card", nameValuePairs.get(i).getValue());
    }
    Log.e("----------", "---------");

    try {
        httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        jsonResponse = httpClient.execute(httpPost, resHandler); // I get org.apache.http.client.HttpResponseException: Not Found 
        Log.e("add edit card response", "-"+jsonResponse);
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return jsonResponse;
}

My Log trace:

org.apache.http.client.HttpResponseException: Not Found
at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:71)
at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:59)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:773)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:743)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:732)
at com.fssd.spot.parser.ParsorClass.addNewCardDetail(ParsorClass.java:1098)
at com.fssd.spot.payment.BillingAddress$AddNewcard.doInBackground(BillingAddress.java:146)
at com.fssd.spot.payment.BillingAddress$AddNewcard.doInBackground(BillingAddress.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:287)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
at java.util.concurrent.FutureTask.run(FutureTask.java:137)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
at java.lang.Thread.run(Thread.java:856)

解决方案

The Api given is invalid so that I get this exception. now I get valid api and working. Thanks.

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