jQuery切换(单击可显示一个div，而隐藏其他div) [英] jQuery toggle (Click to show one div while hiding others)

问题描述

基本思想是我有一堆div，每个div都可以切换(显示/隐藏).

The basic idea is that I have a bunch of div's in which each can be toggled (show/hide).

切换一个div时，我希望当前显示的其他div隐藏，因此一次只能显示一个div.

When one div is toggled I'd like for other div's that are currently being shown to hide, thus only allowing one single div to be shown at a time.

此外，我希望能够在元素外部单击以隐藏打开的div.

In addition I'd like to be able to click outside the element to hide the open div as well.

为了使事情更清楚，我提供了一个示例，该示例当前可以执行我想要的一切，除了打开另一个div时关闭一个div(一次打开一个div功能):

Just to make things clearer I provided an example which currently does everything I want except closing a div when opening another (Only one div open at a time functionality):

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $("div.dropdown-container", $dropdown).toggle();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

推荐答案

您基本上只需要隐藏所有div，除了要切换的div:

You basically just need to hide all divs except the one being toggled:

$(document).ready(function(){

  $('div.dropdown').each(function() {
    var $dropdown = $(this);

    $("a.dropdown-link", $dropdown).click(function(e) {
      e.preventDefault();
      $div = $("div.dropdown-container", $dropdown);
      $div.toggle();
      $("div.dropdown-container").not($div).hide();
      return false;
    });

});
    
  $('html').click(function(){
    $("div.dropdown-container").hide();
  });
     
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="dropdown-1" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-2" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

<div id="dropdown-3" class="dropdown dropdown-processed">
  <a class="dropdown-link" href="#">Options</a>
  <div class="dropdown-container" style="display: none;">
    <ul>
      <li>Item 1</li>
      <li>Item 2</li>
      <li>Item 3</li>
    </ul>
  </div>
</div>

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