如果包含单元格为jQuery,则隐藏表格列 [英] Hiding a table column if the containing cells are empty with jQuery
本文介绍了如果包含单元格为jQuery,则隐藏表格列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下类型的表:
<table id="mytable" width="500" border="1" cellspacing="0" cellpadding="0">
<thead>
<tr>
<th><span>1</th><th><span>2</th><th><span>3</th>
</tr>
</thead>
<tbody>
<tr>
<td><span>1/span></td>
<td><span></span></td>
<td><span>2/span></td>
</tr>
<tr>
<td><span>1</span></td>
<td><span></span></td>
<td><span>2</span></td>
</tr>
<tr>
<td><span>1</span></td>
<td><span></span></td>
<td><span>2</span></td>
</tr>
</tbody>
</table>
我需要做的是-隐藏该表的所有列,其中表单元格包含的<span>
元素为空.我需要完全隐藏单元格,并在顶部放置<th>
元素.在上面的示例中,它是中间一列,但可能有很多,而不仅仅是一个.
What I need to do is - hide all the columns of this table where the <span>
element contained by the table cell is empty. I will need to hide the cell fully, with the <th>
element on the top. In my example above it's the middle column but there may be a lot of them, not only one.
有人可以建议吗?
谢谢.
推荐答案
这应该有效:
$(document).ready(function() {
hideEmptyCols($("#mytable"));
});
function hideEmptyCols(table) {
//count # of columns
var numCols = $("th", table).length;
for ( var i=1; i<=numCols; i++ ) {
var empty = true;
//grab all the <td>'s of the column at i
$("td:nth-child(" + i + ")", table).each(function(index, el) {
//check if the <span> of this <td> is empty
if ( $("span", el).text() != "" ) {
empty = false;
return false; //break out of each() early
}
});
if ( empty ) {
$("td:nth-child(" + i + ")", table).hide(); //hide <td>'s
$("th:nth-child(" + i + ")", table).hide(); //hide header <th>
}
}
}
或(更简单):
function hideEmptyCols(table) {
var rows = $("tr", table).length-1;
var numCols = $("th", table).length;
for ( var i=1; i<=numCols; i++ ) {
if ( $("span:empty", $("td:nth-child(" + i + ")", table)).length == rows ) {
$("td:nth-child(" + i + ")", table).hide(); //hide <td>'s
$("th:nth-child(" + i + ")", table).hide(); //hide header <th>
}
}
}
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