在属性中具有最高值的数组中查找对象的索引 [英] Find index of object in array with highest value in property

问题描述

我有一个包含对象的数组:

I've got an array with objects:

var articles = [];
var article = {};

Simple loop that iterates x times {
        article.text = "foobar";
        article.color = "red";
        article.number = 5;
        articles.push(article);
}

我不知道数组中将有多少个对象，但是它们的属性都有不同的值，我仅在此处提供一些示例.

I have no idea how many objects there will be in my array but they will all have different values for their properties, I just gave some examples here.

问题

我需要找到一种方法来遍历所有这些对象，并检索article.number中具有最高值的对象的索引.我怎样才能做到这一点?我可能只使用javascript，jQuery等.没有其他语言.

I need to find a way to go through all these objects and retrieve the index of the object that has the highest value in article.number. How can I achieve this? I may only use javascript, jQuery, etc.. no other languages.

我猜想这将涉及同时使用$ .grep和Math.max，但是我被困住了，我以前从未使用过$ .grep.

I'm guessing this will involve using both $.grep and Math.max but I'm stuck, I've never worked with $.grep before.

简而言之:

var highestNumber = index of object where article.number is highest

推荐答案

执行此操作的方法有很多，其中Math.max()，$.grep和$.map很少，但是一种易于理解的方法应该可以理解.是只是迭代对象，并检查该值是否大于变量，如果是，则将该变量设置为较高的数字:

There are many ways to do this, Math.max(), $.grep and $.map being a few, but an easy and readable method that should be understandable is to just iterate the object, and check if the value is higher than a variable, if it is, set the variable to the higher number :

var highest = 0;

$.each(articles, function(key, article) {

    if (article.number > highest) highest = article.number;

});

// highest now contains the highest number

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