等待每个jQuery [英] wait for each jQuery

问题描述

我试图在每个语句中使div淡入/淡出.问题在于淡入/淡出完成之前会调用下一个项目.

I'm trying to make a div fade in/out that's within an each statement. The problem is that next item is called before the fade in/out is complete.

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js" type="text/javascript"></script>

<div id='one'>one</div>
<div id='two'>two</div>
<div id='three'>three</div>

<script>
$.each([ "one", "two", "three"], function() {
  console.log( 'start - ' + this );
  animate( this );
  console.log( 'end - ' + this );
});

function animate( id )
{
  box = '#' + id;

  $(box).fadeOut( 500, function( )
  {

    console.log('showing - ' + id);
    $(box).fadeIn( 500 );
    $(box).css('backgroundColor','white');

  });

}
</script>

控制台显示-

start - one
end - one
start - two
end - two
start - three
end - three
showing - one
showing - two
showing - three

我想要类似-

start - one
showing - one
end - one
start - two
showing - two
end - two
start - three
showing - three
end - three

那么在继续下一个值之前，我该如何等待每个'b'完全完成 ?

So how can I wait for each 'each' to be completely finished before moving on to the next value?

推荐答案

您将不得不使用回调-当当前函数完成时将执行的函数.要使用.fadeOut执行此操作，您可以执行以下操作:

Your going to have to use callbacks - functions that get executed when the current function is finished. To do this with .fadeOut you would do:

$('#element').fadeOut( 400, myFunction );

myFunction直到fadeOut完成才被调用.带有$ .get的AJAX调用也可以具有回调函数.

myFunction would not be called until fadeOut was completed. AJAX calls with $.get also can have callback functions.

这是一个可行的示例，尽管我确信有更好的方法:

Here's an example that works, although I'm sure there's a better way:

function animate(myArray, start_index) {

    // Stealing this line from Sam, who posted below.
    if(!start_index) start_index = 0;

    next_index = start_index+1;
    if(next_index > myArray.length) { return; }

    box = '#' + myArray[start_index]; 
    $(box).fadeOut(500, function() { animate(myArray,next_index); });
}

，然后在您的文档中.您将调用:

and then in your document.ready you'd call:

animate(theArray);

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