如何通过jQuery发布单选按钮值 [英] how to POST radio button values through jquery

问题描述

我有以下示例代码:

 while ($row = mysql_fetch_object($result1)) {                  
                    echo '<input type="radio" name="vote" value='.$row->avalue.'/>&nbsp;';
                    echo '<label >'.$row->atitle.'</label><br>';
                }

这将显示4个单选按钮及其标签. 现在，我正在使用以下jquery函数进行POST.

this displays 4 radio buttons alongwith their labels. now I am using the following jquery function to POST.

$("#submit_js").click(function() {
    $.post(
    "user_submit.php", 
    {//how to POST data?}, 
    function(data){
    });
});

我要发布与单选按钮关联的值.但是我该如何选择值呢? 我如何确定选择了哪个单选按钮并发布它?

I want to post the value associated with the radio button. but how do i select the value? how do i determine what radio button is selected and POST it?

推荐答案

$("[name='vote']:checked").val()将为您提供所选单选按钮的值.

$("[name='vote']:checked").val() will get you the value of the selected radio button.

$("#submit_js").click(function() {
  $.post(
  "user_submit.php", 
  {vote: $("[name='vote']:checked").val()}, 
  function(data){
  });
});

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