如何绘制路径工会的轮廓 [英] How to draw the contour of a union of Path

问题描述

您好，我有六角路径的包和要绘制的路径工会的轮廓（境）。我想用地区，工会的路径，然后一起用得到getBoundaryPath（）的边界产生的路径，但它汲取什么。
因此，有人可以告诉我，我怎么能有我所有的路径对象的工会的轮廓（境）？

  @覆盖
保护无效的onDraw（帆布油画）{
    super.onDraw（画布）;
    //如果（pmBack！= NULL）{
    // canvas.drawBitmap（pmBack，新的Matrix（），涂料）;
    //}    如果（mCells！= NULL）{        的for（int i = 0; I＆LT; mCells.length;我++）{
            最后HexCell电池= mCells [I]
            如果（细胞！= NULL）{
                最终的PointF P = cell.getDrawPoint（）;
                paint.setColor（cell.mColor）;                路径path = drawHexagon（cell.mSize，mCenterX + p.x，mCenterY + p.y）;
                canvas.drawPath（drawHexagon（cell.mSize，mCenterX + p.x，mCenterY + p.y），涂料）;                如果（我== 0）{
                    region.setPath（路径，mClip）;
                }其他{
                    region2.setPath（路径，mClip）;
                    region.op（REGION2，Op.UNION）;
                }
            }
        }
        canvas.drawPath（region.getBoundaryPath（），paintContour）;
    }}私人路径drawHexagon（最终浮动大小，浮动的centerX，浮centerY）{
    路径path =新路径（）;
    的for（int i = 0; I＆LT; = 6;我++）{
        双角= 2 * Math.PI / 6 *（1 + 0.5）;
        浮动x_i =（浮点）（+的centerX大小* Math.cos（角度））;
        浮动y_i =（浮点）（centerY +尺寸* Math.sin（角度））;
        如果（我== 0）{
            path.moveTo（x_i，y_i）;
        }其他{
            path.lineTo（x_i，y_i）;
        }
    }    返回路径;
}
 

解决方案

尝试使用

 路径轮廓= r​​egion.getBoundaryPath（）;
路径的新路径=新路径（）;
字模=新的Matrix（）;
matrix.setScale（1，1，0，0）;
outline.transform（矩阵的新路径）;
canvas.drawPath（的新路径，油漆）;
 

而不是使用 getBoundaryPath 直接

Hello i have a pack of Hexagon Path and a want to draw the contour(border) of the union of those Path. I thought of using Region, to union the Path together then get the border resulting Path with getBoundaryPath(), but it draw nothing. So can someone tell me how can I have the contour(border) of the union of all my Path objects ?

 @Override
protected void onDraw(Canvas canvas) {
    super.onDraw(canvas);
    // if (pmBack != null) {
    // canvas.drawBitmap(pmBack, new Matrix(), paint);
    // }

    if (mCells != null) {

        for (int i = 0; i < mCells.length; i++) {
            final HexCell cell = mCells[i];
            if (cell != null) {
                final PointF p = cell.getDrawPoint();
                paint.setColor(cell.mColor);

                Path path = drawHexagon(cell.mSize, mCenterX + p.x, mCenterY + p.y);
                canvas.drawPath(drawHexagon(cell.mSize, mCenterX + p.x, mCenterY + p.y), paint);

                if (i == 0) {
                    region.setPath(path, mClip);
                } else {
                    region2.setPath(path, mClip);
                    region.op(region2, Op.UNION);
                }
            }
        }
        canvas.drawPath(region.getBoundaryPath(), paintContour);
    }

}

private Path drawHexagon(final float size, float centerX, float centerY) {
    Path path = new Path();
    for (int i = 0; i <= 6; i++) {
        double angle = 2 * Math.PI / 6 * (i + 0.5);
        float x_i = (float) (centerX + size * Math.cos(angle));
        float y_i = (float) (centerY + size * Math.sin(angle));
        if (i == 0) {
            path.moveTo(x_i, y_i);
        } else {
            path.lineTo(x_i, y_i);
        }
    }

    return path;
}

解决方案

Try using

Path outline = region.getBoundaryPath();
Path newpath = new Path();
Matrix matrix = new Matrix();
matrix.setScale(1, 1, 0, 0);
outline.transform(matrix,newpath);
canvas.drawPath(newpath, paint);

instead of using getBoundaryPath directly.

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