SyntaxError:JSON.parse:JSON数据第1行第2列的意外字符-FireBug报告此错误.有什么办法吗? [英] SyntaxError: JSON.parse: unexpected character at line 1 column 2 of the JSON data -- FireBug reports this error. Any solution?

问题描述

我已经使用Laravel Response :: json生成JSON响应.

I have used Laravel Response::json to generate a JSON response.

return Response::json(array('subjects' => $subjects, 'year' => $year, 'sem' => $sem));

运行请求时，我得到一个有效的JSON(在JSONLint中进行了测试)作为响应.

When I run the request, I get a valid JSON (tested in JSONLint) as a response.

但是以下jQuery方法失败:$.parseJSON(data)

But the following jQuery method fails: $.parseJSON(data)

我在FireBug中收到以下错误:

I get the following error in FireBug:

SyntaxError:JSON.parse:JSON数据第1行第2列的意外字符

SyntaxError: JSON.parse: unexpected character at line 1 column 2 of the JSON data

我收到的回复:

{
    "subjects": [
        {
            "id": 1,
            "name": "Control Systems",
            "semester": 1,
            "year": 3,
            "branch_id": 4
        },
        {
            "id": 2,
            "name": "Analog Communications",
            "semester": 1,
            "year": 3,
            "branch_id": 4
        },
        {
            "id": 3,
            "name": "Linear IC Applications",
            "semester": 1,
            "year": 3,
            "branch_id": 4
        },
        {
            "id": 4,
            "name": "Antennas & Wave Propagation",
            "semester": 1,
            "year": 3,
            "branch_id": 4
        }
    ],
    "year": 3,
    "sem": 2
}

以及我要解析的代码:

$(document).ready(function() {
    $('#branchAndSubjects').click(function() {
        $.post('/findBranchAndSubjects', {
            roll: roll,
            _token: "{{csrf_token()}}"
        }, function(data) {
            var subjects = $.parseJSON(data);
        });
    });
});

推荐答案

如果您正在ajax成功处理程序中执行$.parseJSON(data) ，因为您正在ajax中执行$.parseJSON(data)成功处理程序，问题几乎可以肯定是jQuery已经已经为您解析了它. jQuery将查看响应的Content-Type，如果响应为application/json，它将对其进行解析，并将解析的结果提供给成功处理程序.如果将其传递给$.parseJSON，将会发生的第一件事是它将被转换回字符串(对于您来说是"[object Object]")，然后$.parseJSON将无法解析该字符串.

If you're doing the $.parseJSON(data) in an ajax success handler Since you're doing the $.parseJSON(data) in an ajax success handler, the problem is almost certainly that jQuery has already parsed it for you. jQuery will look at the Content-Type of the response and, if it's application/json, it will parse it, and provide the parsed result to your success handler. The first thing that will happen if you pass that into $.parseJSON will be that it will get converted back to a string ("[object Object]", in your case), which $.parseJSON will then fail to parse.

只需按原样使用data，就已经有了对象，这要归功于自动解析:

Just use data as-is, it's already an object, thanks to the automatic parsing:

$(document).ready(function() {
    $('#branchAndSubjects').click(function() {
        $.post('/findBranchAndSubjects', {
            roll: roll,
            _token: "{{csrf_token()}}"
        }, function(data) {
            console.log(data.year);             // 3
            console.log(data.subjects.length);  // 4
            console.log(data.subjects[0].name); // Control Systems
        });
    });
});

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