Ajax调用永远不会成功 [英] Ajax call is never success

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本文介绍了Ajax调用永远不会成功的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

Iam facnigg并遇到ajax问题,我正在处理联系表单,而ajax调用存在问题, 即使字段都正确键入,该呼叫也不会成功. 我尝试了几件事,但没有任何效果 Somene可以给我建议..

Iam facnigg and issue with ajax, Im working on a contact form and I have an issue with the ajax call, The call is never succseed, even if the field are all typed correctly. I tried few things but nothing is working Somene can give me an advice..?

非常感谢.

$.ajax({
  url: "assets/contact_form/process-contact.php",
  type: "POST",
  dataType: "html",
  data: userData,

  beforeSend: function () {
    $( sb ).html('Sending...');
  },
  success: function (response) {

    if (response == true) {

      setTimeout(function () {

        window.location = 'index.html';

      }, 1000);

    } else {

      $( sb ).html('Can not send, please try latter'); //IT GOES STRIGHT TO HERE

    }
  }
});

 }

});

这是php代码:

<?php

  $userData['name'] = filter_var(trim($_POST['name']), 
    FILTER_SANITIZE_STRING);
     $userData['email'] = filter_var(trim($_POST['email']), 
   FILTER_VALIDATE_EMAIL);
      $userData['phone'] = filter_var(trim($_POST['phone']), 
  FILTER_SANITIZE_STRING);
 $userData['message'] = filter_var(trim($_POST['message']), 
 FILTER_SANITIZE_STRING);

 if( ! in_array( null, $userData ) ){

$my_email = 'roni.itzhaik@gmail.com';


$nameRegx = "/^[' a-zא-ת]+(\s[' a-zא-ת]+)*$/i";
 $phoneRegx = "/^(?:0(?!(5|7))(?:2|3|4|8|9))(?:-?\d){7}$|^(0(?=5|7)(?:-?\d)
{9})$/";

  if( strlen($userData['name']) > 2 &&  strlen($userData['name']) < 70 && 
 preg_match($nameRegx, $userData['name']) ) {

   if( preg_match($phoneRegx, $userData['phone']) ){

  if( strlen($userData['message']) > 2 ){

      $subject = 'Message from ' . $userData['name'] ;
       $message_phone= $userData['message'].'Phone number: 
    '.$userData['phone'];
      $headers = 'From: ' . $userData['email']. "\r\n";

      mail($my_email, $subject, $message_phone,  $headers);
    // send mail
    // Save data to db (DON'T FORGET TO CLEAN AGAINST SQL INJECTIONS!!!)
    echo true;

          }}}}

推荐答案

最好返回一个对象:

echo json_encode(['success' => true]);

然后,您的成功回调中的检查将如下所示:

Then the check in your success callback will looks like :

if (response.success){
   //Your logic
}

希望这会有所帮助.

这篇关于Ajax调用永远不会成功的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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