如何从nodejs在ajax中进行响应 [英] how to take a response in ajax from nodejs

问题描述

我正在尝试提交表单，然后它通过AJAX发送状态success. 但是，当我在提交表单后从NodeJS发送状态时，它没有到达AJAX代码，因为我已经放置了alert()语句来检查它是否到达了它.警报不会触发，但会直接打印我在send('this text is printed')中编写的值.

I am trying submit a form and after that it send a status success via AJAX. But when I'm sending a status from NodeJS after submitting the form it does not reach the AJAX code, as I have put an alert() statement to check if it reaches it. The alert is not triggered, but it directly prints that value which I wrote in send('this text is printed').

我的test.js文件是

My test.js file is

$(document).ready(function() {
    $('#form_submit').click(function() {
        $.ajax({
            url: '/submitForm',
            type: 'POST',
            contentType: 'application/json',
            success: function(result) {
                alert(result.status);
                if (result.status === "success") {
                    alert("success");
                    window.location = '/nextPage';

                } else {
                    alert("failure");
                }

            },
            error: function(err) {
                alert('error');
            }
        })
    });
});

下面是我的NodeJS代码

and my NodeJS code is given below

app.post('/submitForm', function(req, res) {
    // submitted form to database
    var form = new Form({
        name: req.body.name,
        email: req.body.email,
        number: req.body.number,
    });
    form.save(function(err) {
        if (err) {
            throw new Error(err);
        } else {
            res.send({
                status: 'success',
                message: 'successfully form created'
            });
        }
    });
});

推荐答案

您必须将res.send()更改为res.json()才能发送JSON数据.

You have to change res.send() to res.json() in order to be able to send JSON data.

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