jQuery验证与占位符Polyfill不兼容吗? [IE9错误] [英] Jquery Validate Incompatible with Placeholder Polyfill? [IE9 Bug]

问题描述

我目前正在将 Mathias Bynens的占位符Polyfill与 jquery.validate插件(v1.11.1)，并且使用 Internet Explorer 9 遇到了令人沮丧的错误.

I'm currently using the Placeholder Polyfill by Mathias Bynens in combination with the jquery.validate plugin (v1.11.1) and am running into a frustrating error with Internet Explorer 9.

如果我的type="password"字段定义了非空的placeholder属性，则无法获得必填字段的验证，以对我的type="password"字段起作用.输入一个值并且占位符文本消失后，其余的验证就可以正常工作.

I cannot get required field validation to work on my type="password" fields if they have a non-empty placeholder attribute defined. Once a value is input and the placeholder text disappears, the remaining validation works fine.

可在此处找到此代码的实时演示

JS

$('input').placeholder(); // init placeholder plugin
signupFormValidator = $('form').validate(); // init validation

HTML

<form>
  <input class="required" type="text" name="test" id="test" placeholder="test"><br>
  <input class="required" type="password" name="password" id="password" placeholder="password"><br>
  <input class="required" type="password" name="confirm"  id="confirm"  placeholder="confirm"><br>
  <input type="submit">
</form>

推荐答案

编辑:此修复程序引入了Firefox中的错误.请参阅下面的评论.

edit: this fix introduces bugs in Firefox. Please see comment below.

为了解决这个问题，我最终使用了一些我自己烤的相当笨拙的jQuery:

To deal with this, I ended up using some fairly hacky jQuery I baked myself:

$('#password, #confirm').keyup(function() {
    var $input = $(this);
    if ($input.attr('type') === 'text') {
        if ($input.val().length > 0) {
            $input.attr('type', 'password');
        }
    } else if ($input.val() === "") {
        $input.attr('type', 'text');
    }
});

这是在将字段type设置为文本"而不​​是密码"，从而有效地解决了令人讨厌的占位符问题.

What this is doing, is setting the field type to "text" rather than "password", effectively clearing up that pesky placeholder issue.

次要问题:在开始向输入中输入文本时，密码的第一个字符会短暂显示为纯文本.

Minor issue: the first character of the password displays as plain-text briefly when starting to enter text into the input.

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