Ajax调用后返回视图 [英] return view after ajax call

问题描述

使用jquery进行异步调用后，如何返回特殊视图?

after an async call with jquery how can I return a particolar view?

这是我的来电者视图:

<script type="text/javascript">

    function Run() {

        $.ajax({
            type: "POST",
            cache: false,
            url: "/Home/Run",
            data: $("#form_run").serializeArray(),
            dataType: "json"
        });

    }

</script>
<form action="javascript:return true;" method="post" id="form_run">
    <input type="text" id="nome" name="nome" />
    <input type="text" id="cognome" name="cognome" />
    <input type="submit" name="submit" value="Run" onclick="Run();" />
</form>

这是我的控制器操作:

    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Run(string nome, string cognome)
    {
        return View("Result");
    }

无法显示视图结果" 怎么样?

can not display view "Result" How?

推荐答案

您不能从异步调用中返回View. Ajax请求的目的是避免执行整个页面周期.

You can not return a View from an asynchronous call. An ajax request is meant to avoid doing an entire page cycle.

如果您要返回新的View，则只需返回POST.

You should just do a POST back if you want a new View to be returned.

另一个选择是在ajax调用成功后进行回调，并将window.location设置为新的View，以便页面将GET设置为新的View.

The other option would to be have a callback upon success of the ajax call and set the window.location to the new View so the page does a GET to the new View.

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